The solution of dydx + y tan(x) = sec(x) is :
ysecx = tanx + c
ytanx = secx + c
tanx = ytanx + c
xsecx = tany + c
The solution of dydx = ax + hby + k represents a parabola, when :
a = 0, b = 0
a = 1, b = 2
a = 0, b ≠ 0
a = 2, b = 1
An integrating factor of the differential equation xdydx + ylogx = xexx12logx, (x > 0) is :
xlog(x)
xlogx
elogx2
ex2
The solution of edydx = x + 1, y(0) = 3 is :
y = xlog(x) - x + 2
y = (x + 1)logx + 1 - x + 3
y = x + 1logx + 1 + x + 3
y = xlogx + x + 3
Solution of the differential equation dydxtany = sinx + y + sinx - y is :
secy + 2cosx = c
secy - 2cosx = c
cosy - 2sinx = c
tany - 2secy = c
Solution of the differential equation dydx + yx = sinx is :
xy + cosx = sinx + c
xy - cosx = sinx + c
xycosx = sinx + c
xy - cosx = cosx + c
The solution of the differential equation xdydx + 2y = x2 is :
y = x2 + c4x2
y = x24 + c
y = x2 + cx2
y = x4 + c4x2
y = - A cos(5x) + B sin(5x) satisfies the differential equation :
d2ydx2 + 10dydx + 25y = 0
d2ydx2 - 10dydx + 25y = 0
d2ydx2 - 25y = 0
d2ydx2 + 25y = 0
The order and degree of the differential equation sinxdx + dy = cosxdx - dy is :
(1, 2)
(2, 2)
(1, 1)
(2, 1)
An integrating factor of the differential equation, (1 + y + x2y)dx + (x + x3)dy = 0 is :
logx
x
ex
1x
B.
dyx + x3 = - dx1 + y + x2y⇒ dydx = - 1 + y + x2yx + x3⇒ dydx + y1 + x2x1 + x2 = - 1x1 + x2⇒ dydx + yx = - 1x1 + x2∴ IF = e∫1xdx = elogx = x