The solution of the differential equation is :
y(1 + x2) = c + tan-1(x)
A.
y(1 + x2) = c + tan-1(x)
The solution of the differential equation sec2(x)tan(y))dx + sec2(y)tan(x))dy = 0 is :
None of these
To reduce the differential equation to the linear form, the substitution is :
v = yn
v = yn - 1