∫sinxsinx - adx is equal to : from Mathematic

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 Multiple Choice QuestionsMultiple Choice Questions

271.

e- logxdx is equal to :

  • e- log(x) + C

  • - xe- log(x) + C

  • elog(x) + C

  • logx + C


272.

ax2a- x - axdx is equal to :

  • 1logasin-1ax + c

  • 1logatan-1ax + c

  • 2a- x - ax + c

  • logax - 1 + c


273.

If g(x) = fx - f- x2  defined over [- 3, 3], and f(x) = 2x2 - 4x + 1, then - 33gxdx is equal to :

  • 0

  • 4

  • - 4

  • 8


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274.

sinxsinx - adx is equal to :

  • xcosa - sinalogsinx - a + c

  • xsina + c

  • xsina + sinalogsinx - a + c

  • xcosa + sinalogsinx - a + c


D.

xcosa + sinalogsinx - a + c

Let I  = sinxsinx - adxPut x - a = t dx = dt and x = t +a I = sint + asintdx      = sintcosa + costsinasintdt      = cosa1dt + sinacostsintdt      = cosa . t + sinalogsint + c      = x - acosa + sinalogsinx - a + c      = xcosa + sinalogsinx - a + c


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275.

f'xfxlogfxdx is equal to :

  • fxlogfx

  • f(x) . log(f(x)) + c

  • loglogfx + c

  • 1loglogfx + c


276.

ex2 + exex + 1dx is equal to :

  • log1 + ex2 + ex + c

  • log2 + ex1 + ex + c

  • 1 + ex2 + ex + c

  • 2 + ex1 + ex + c


277.

If In0π4tannθ, then Iθ + I6 is equal to :

  • 17

  • 14

  • 15

  • 16


278.

ex - e- xex + e- xlogcoshx is equal to :

  • logtanhx

  • 2logex + e- x + c

  • 2logex - e- x + c

  • loglogcoshx + c


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279.

- 1212cosxlog1 + x1 - xdx = k . log2, then k equals to

  • 0

  • - 1

  • - 2

  • 12


280.

0π2cosθ4 - sin2θ is equal to :

  • π2

  • π6

  • π3

  • π5


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