By the application of Simpson's one - third rule for numerical in

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

351.

cos3x . elogsinxdx is equal to

  • - sin4x4 + c

  • - cos4x4 + c

  • esinx4 +c

  • None of the above


352.

The value of 0π2cos3x + 12cosx - 1dx is

  • 2

  • 1

  • 12

  • 0


353.

The value of 01tan-12x - 11 + x - x2dx is

  • 1

  • 0

  • - 1

  • None of the above


Advertisement

354.

By the application of Simpson's one - third rule for numerical integration, with two subintervals, the value of 01dx1 +x is

  • 1736

  • 1725

  • 2536

  • 1724


C.

2536

Since, the iven integration is divided into two subintervals.

i.e., h = 1 - 02 = 120111 +xdx = h3y0 + y2 + 4y1At    x = 0, y = 1       x = 12, y1 = 23and x = 1, y2 = 12 0111 +xdx = 12 . 31 + 12 + 423                         = 1632 + 83 = 2536


Advertisement
Advertisement
355.

xe - 1 + ex - 1xe + exdx is equal to

  • logxe + ex +c

  • elogxe + ex +c

  • 1elogxe + ex +c

  • None of the above


356.

The value of π4π2exlogsinx + cotxdx is

  • eπ4log2

  • - eπ4log2

  • 12eπ4log2

  • - 12eπ4log2


357.

Considering four sub-intervals, the value of 0111 +xdx by Trapezoidal rule, is

  • 0.6870

  • 0.6677

  • 0.6977

  • 0.5970


358.

By Simpson's rule, the value of 12dxx dividing the interval (1, 2) into four equal parts, is

  • 0.6932

  • 0.6753

  • 0.6692

  • 7.1324


Advertisement
359.

The value of xsinxsec3xdx is

  • 12sec2x - tanx + c

  • 12xsec2x - tanx + c

  • 12xsec2x + tanx + c

  • 12sec2x + tanx + c


360.

The value of 0xxsin3xdx is

  • 4π3

  • 2π3

  • 0

  • None of these


Advertisement