If ∫01fxdx = 5, then the value&

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 Multiple Choice QuestionsMultiple Choice Questions

491.

sinxcosx1 - sin4xdx is equal to

  • 12sin-1sin2x + C

  • 12cos-1sin2x + C

  • tan-1sin2x + C

  • tan-12sin2x + C


492.

etan-1x1 + x1 +x2dx is equal to

  • xetan-1x +c

  • etan-1x +c

  • 12etan-1x +c

  • 12xetan-1x +c


493.

cscx - acscxdx is equal to

  • - 1sinalogsinxcscx - a +c

  • - 1sinalogsinx - asinx +c

  • 1sinalogsinxcscx - a +c

  • 1sinalogsinx - asinx +c


494.

If f(x) = - 1xtdt, then for any x  0, f(x) is equal to

  • 1 - x2

  • 121 +x2

  • 1 + x2

  • 121 - x2


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495.

134 - xx + 4 - xdx is equal to

  • 1

  • 3

  • 2

  • 0


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496.

If 01fxdx = 5, then the value of ... + 01x9fx10dx is equal to

  • 125

  • 625

  • 275

  • 55


D.

55

Given, 01fxdx = 5Let I = 100 01x9fx10dxPut x10 = t  10x9dx = dt I = 10001ft10dt       = 10 × 5 = 50 01fxdx + 10001x9fx10dx       = 5 + 50 = 55


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497.

If fxsinx . cosxdx = 12b2 - a2logfx +c, where c is the constant of integration, then f(x) is

  • 2abcos2x

  • 2b2 - a2cos2x

  • 2absin2x

  • 2b2 - a2sin2x


498.

If xxx + 1dx = ktan-1m, then (k, m) is

  • (2, x)

  • (1, x)

  • 1, x

  • 2, x


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499.

0π4sinx + cosx3 + sin2xdx is

  • 14log3

  • log3

  • 12log3

  • 2log3


500.

01x1 - x32dx is

  • - 235

  • 435

  • 2435

  • - 835


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