∫cos2x - 1cos2x + 1dx is equal to f

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 Multiple Choice QuestionsMultiple Choice Questions

541.

02x2dx is equal to

  • 2 - 2

  • 2 + 2

  • 2 - 1

  • - 2 - 3 + 5


542.

In = 0π4tannxdx, then limnnIn + In + 2 equals

  • 1/ 2

  • 2 sq units

  • 3 sq units

  • 4 sq uits


543.

010πsinxdx is equal to

  • 20

  • 8

  • 10

  • 18


544.

If I = x0x0 + nhydx, then by Trapezoidal rule I is equal to

  • hy0 + yn + 2y1 + y2 + ... + yn - 1

  • h12y0 + yn + 2y1 + y2 + ... + yn - 1

  • h2y0 + yn + 2y1 + y2 + ... + yn - 1

  • hy0 + yn + 2y1 + y2 + ... + yn - 1


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545.

dx1 - x2 is equal to

  • tan-1x + c

  • sin-1x + c

  • 12log1 + x1 - x + c

  • 12log1 - x1 + x + c


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546.

cos2x - 1cos2x + 1dx is equal to

  • tanx - x + c

  • x + tanx + c

  • x - tanx + c

  • - x - cotx + c


C.

x - tanx + c

cos2x - 1cos2x + 1dx= - cos2x - 1cos2x + 1dx= - 2sin2x2cos2xdx= - tan2xdx= - sec2x - 1dx= - tanx + x + c= x - tanx + c


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547.

Suppose f is such that f( - x) = - f(x), for every real x and 01fxdx = 5, then - 10ftdt is equal to

  • 10

  • 5

  • 0

  • - 5


548.

If f(y) = ey, g(y) = y, y > 0 and F(t) = 0tft - y . gydy, then 

  • F(t) = 1 - e- t(1 + t)

  • F(t) = et - (1 + t)

  • F(t) = tet

  • F(t) = te- t


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549.

Let f(x) be a function satisfying f'(x) = f(x) with f(0) = 1 and g(x) be a function that satisfies f(x) + g(x) = x2. Then, the value of the integeral 01fxgxdx is

  • e - e22 - 52

  • e + e22 - 32

  • e - e22 - 32

  • e + e22 + 52


550.

- 10dxx2 + 2x + 2 is equal to

  • 0

  • π4

  • π2

  • - π4


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