If fx = 1x2∫3x2t - 3f'tdt, then

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 Multiple Choice QuestionsMultiple Choice Questions

631.

 1 + x - x- 1ex + x- 1dx is equal to˸

  • 1 + xex + x- 1 + C

  • x - 1ex + x- 1 + C

  • - xex + x- 1 + C

  • xex + x- 1 + C


632.

- 22xdx is equal to

  • 1

  • 2

  • 3

  • 4


633.

01sin2tan-11 + x1 - xdx is equal to

  • π6

  • π4

  • π2

  • π


634.

033x + 1x2 + 9dx is equal to :

  • log22 + π12

  • log22 + π2

  • log22 + π6

  • log22 + π3


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635.

If [2, 6] is divided into four intervals of equal length, then the approximate value of 261x2 - xdx using Simpson's rule, is

  • 0.3222

  • 0.2333

  • 0.5222

  • 0.2555


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636.

If fx = 1x23x2t - 3f'tdt, then f't, then f'(3) is equal to

  • - 1 2

  • - 13

  • 12

  • 13


C.

12

Given that,fx = 1x23x2t - 3f'tdt + 3x2t - 3f'tdtOn differentiating both sides w. r. t. x, we getf'x = 1x2ddx3x2t - 3f'tdt + 3x2t - 3f'tdtddx1x2 f'x = 1x22t - 3f't - 2x33x2t - 3f'tdtAt x = 3 f'3 = 1326 - 3f'3 - 0 4 f'33 = 23   f'3 = 12


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637.

dxx + 100x + 99 = fx + c  fx

  • 2(x + 100)1/2

  • 3(x + 100)1/2

  • 2tan-1x + 99

  • 2tan-1x + 100


638.

3 - x21 - 2x + x2exdx = exfx + c  fx

  • 1 + x1 - x

  • 1 - x1 + x

  • 1 - xx - 1

  • x - 11 + x


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639.

cotxsinxcosxdx = - fx + c  fx

  • 2tanx

  • - 2tanx

  • - 2cotx

  • 2cotx


640.

- π2π2log2 - sinθ2 + sinθ is equal to

  • 0

  • 1

  • 2

  • - 1


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