sinx + 8cosx4sinx + 6cosxdx = ? fr

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 Multiple Choice QuestionsMultiple Choice Questions

651.

0π2 dx1 + tan3x = ?

  • π

  • π2

  • π4

  • 3π2


652.

- 11 coshx1 +e2xdx = ?

  • 0

  • 1

  • e2 - 12e

  • e2 + 22e


653.

If ex - 1ex + 1dx = fx + c, then fx is equal to

  • 2logex - 1

  • 2loge2x - 1

  • 2logex + 1 - x

  • 2loge2x + 1


654.

tan-11 - x1 + xdx = ?

  • 12xcos-1x - 1 - x2 +c

  • 12xcos-1x + 1 - x2 +c

  • 12xsin-1x - 1 - x2 +c

  • 12xsin-1x + 1 - x2 +c


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655.

sinx + 8cosx4sinx + 6cosxdx = ?

  • x + 12log4sinx + 6cosx + c

  • 2x + log2sinx + 3cosx + c

  • x + log2sinx + 3cosx + c

  • 12log4sinx + 6cosx + c


A.

x + 12log4sinx + 6cosx + c

Let I = sinx + 8cosx4sinx + 6cosxdxWe can writesinx + 8cosx = A4sinx + 6cosx + Bddx4sinx + 6cosxsinx + 8cosx = A4sinx + 6cosx + B4cosx - 6sinxOn equating the coefficient of sinx and cosx,we get1 = 4A - 6B,     8 = 6A +4B A = 1, B = 12 I = 4sinx + 6cosx + 124cosx - 6sinx4sinx + 6cosxdx        = 1 + 124cosx - 6sinx4sinx + 6cosx dx        = x + 12log4sinx + 6cosx  + c


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656.

If ft = - tte- x2dx, then limtft = ?

  • 1

  • 12

  • 0

  • - 1


657.

02πsin6xcos5xdx  = ?

  • 2π

  • π2

  • 0

  • - π


658.

If ex1 - sinx1 - cosxdx = fx + constant, then f(x) is equal to

  • excotx2 + c

  • e-xcotx2 + c

  • - excotx2 + c

  • - e- xcotx2 + c


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659.

If Inxnecxdx for n  1, then cIn + n . In - 1 is equal to

  • xnecx

  • xn

  • ecx

  • xn + ecx


660.

If ex1 + x . sec2xexdx = f(x) + constant, then f(x) is equal to

  • cosxex

  • sinxex

  • 2tan-1x

  • tanxex


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