If cotcos-1x = sectan-1ab2 - a2, then x is equal to
b2b2 - a2
a2b2 - a2
2b2 - a2a
2b2 - a2b
Number of solutions ofthe equation
tan-112x + 1 + tan-114x + 1 = tan-12x2 is
1
2
3
4
The value of tan-112 + tan-113 + tan-178 is
tan-178
cot-115
tan-115
tan-12524
If tan-1x - 1 + tan-1x + tan-1x + 1 = tan-13x, then x is
± 12
0, 12
0, - 12
0, ± 12
D.
tan-1x - 1 + tan-1x + tan-1x + 1 = tan-13x⇒ tan-1x - 1 + tan-1x = tan-13x - tan-1x + 1⇒ tan-1x - 1 + x1 - x - 1x = tan-13x - x + 11 + 3xx + 1⇒ 1 + 3x2 + 3x2x - 1 = 1 - x2 + x2x - 1⇒ 2x - 14x2 + 2x = 0⇒ x = 0, ± 12
The domain of the function sin-1log2x22 is
[- 1, 2] - {0}
[- 2, 2] - (- 1, 1)
[- 2, 2] - {0}
[1, 2]
3tan-1a is equal to
tan-13a + a31 + 3a2
tan-13a - a31 + 3a2
tan-13a + a31 - 3a2
tan-13a - a31 - 3a2
The value of sinsin-113 + sec-13 + costan-112 + tan-12 is :
The value of cot-19 + csc-1414 is given by :
0
π4
π2
tan-12
cos-112 + 2sin-112 is equal to :
π6
π3
2π3
A particle possess two velocities simultaneously at an angle of tan-1125; to each other. Their resultant is 15 m/s. If one velocity is 13 m/s, then the other will be :
5 m/s
4 m/s
12 m/s
13 m/s