If sin-1x + cot-112 = π2, then value

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 Multiple Choice QuestionsMultiple Choice Questions

161.

The value of cot-11 + sinx + 1 - sinx1 + sinx - 1 - sinx is equal to

  • x3

  • x4

  • 1

  • x2


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162.

If sin-1x + cot-112 = π2, then value of x will be

  • 0

  • 15

  • 25

  • 32


B.

15

Given, sin-1x + cot-112 = π2 sin-1x = tan-112       tan-1θ + cot-1θ = π2 x = sintan-112 x = sinsin-115 x = 15


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163.

The value of tan2tan-115 - π4 is

  • 177

  • - 177

  • 717

  • - 717


164.

The value of sin-145 + 2tan-123 is

  • π3

  • π2

  • π6

  • None of these


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165.

The value of sin2tan-113 + costan-122 will be

  • 1312

  • 1415

  • - 1415

  • 1213


166.

tan-1x - 2x - 3 + tan-1x + 2x + 3 = π4, then x = ?

  • ± 12

  • ± 72

  • ± 27

  • None of these


167.

sec2tan - 12 + cosec2 cot - 13 is equal to 

  • 3

  • 10

  • 15

  • 20


168.

sinh - 1x1 - x2 is equal to 

  • coth - 1x

  • sinh - 1x

  • - tanh - 1x

  • tanh - 1x


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169.

If sin-1x - cos-1x = π6, then x is equal to

  • 12

  • 32

  • - 12

  • - 32


170.

sinh-1232 is equal to

  • log3 + 8

  • log3 - 8

  • log2 + 18

  • log8 + 27


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