61.

Probability of getting a total of 7 or 9 in a single throw of two dice is

• $\frac{5}{18}$

• $\frac{1}{6}$

• $\frac{1}{9}$

• None of these

Let A and B be two events of an experiment $\mathrm{P}\left(\mathrm{A}\right) = \frac{1}{4}, \mathrm{P}\left(\mathrm{A} \cup \mathrm{B}\right) = \frac{1}{2}$, then the value of $\mathrm{P}\left(\frac{\mathrm{B}}{{\mathrm{A}}^{\mathrm{C}}}\right)$ is

• $\frac{2}{3}$

• $\frac{1}{3}$

• $\frac{5}{6}$

• $\frac{1}{2}$

A die is rolled three times. The probability of getting a larger number than the previous number is

• $\frac{5}{216}$

• $\frac{5}{54}$

• $\frac{1}{6}$

• $\frac{5}{36}$

If A and B are mutually exclusive events, then P(A/B) is equal to

• 0

• 1

• $\frac{\mathrm{P}\left(\mathrm{A} \cap \mathrm{B}\right)}{\mathrm{P}\left(\mathrm{A}\right)}$

• $\frac{\mathrm{P}\left(\mathrm{A} \cap \mathrm{B}\right)}{\mathrm{P}\left(\mathrm{B}\right)}$

If $\mathrm{P}\left(\mathrm{A}\right) = \frac{1}{2}, \mathrm{P}\left(\mathrm{B}\right) = \frac{1}{3} \mathrm{and} \mathrm{P}\left(\mathrm{A} \cap \mathrm{B}\right) = \frac{1}{4}$, then the value of $\mathrm{P}\left(\frac{\mathrm{B}}{\mathrm{A}}\right)$ wll be

• 1

• 0

• $\frac{1}{2}$

• $\frac{1}{3}$

Six boys and six girls sit in a row. The probability that the boys and girls sit alternately will be

• $\frac{1}{462}$

• $\frac{1}{924}$

• $\frac{1}{2}$

• None of these

In a regular hexagon, 3 vertices out of 6 are randomly chosen. The probability that the triangle formed out of these three vertices will be an equilateral triangle, is

• $\frac{1}{2}$

• $\frac{1}{5}$

• $\frac{1}{10}$

• $\frac{1}{20}$

In a competition A, B, C are participating the probability that A wins is twice that of B, the probability that B wins is twice that of C, then probability that A loses is

• $\frac{1}{7}$

• $\frac{2}{7}$

• $\frac{4}{7}$

• $\frac{3}{7}$

The probability that a number selected at random from the set of numbers (1, 2, 3, ... , 100) is a cube, is

• $\frac{1}{25}$

• $\frac{2}{25}$

• $\frac{3}{25}$

• $\frac{4}{25}$

Two dice are rolled simultaneously. The probability that the sum of the two numbers on the dice is a prime number, is

• $\frac{5}{12}$

• $\frac{7}{12}$

• $\frac{9}{12}$

• 0.25