A random variable X takes the values 0, 1 and 2. If P(X = 1) = P(

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 Multiple Choice QuestionsMultiple Choice Questions

231.

A fair coin is tossed n times. If the probability of getting 7 heads is equal to the probability of getting 9 heads, then the value of n will be

  • 8

  • 13

  • 15

  • None of these


232.

The probabilities of solving a question by three students
are 12, 14, 16 respectively. What is the probability that the question is solved ?

  • 3548

  • 148

  • 1116

  • 211


233.

A and B are two independent events. Probability of happening of both A and B is 1/6 and probability of happening of neither of them is 1/3, then the probability of events A and B are respectively

  • 12 and 13

  • 15 and 16

  • 12 and 16

  • 23 and 14


234.

If m things are distributed among a men and b women. Then, the chance that the number of things received by men is odd, is

  • b - am - b + am2b + am

  • b + am - b - am2b + am

  • b + am - b - amb + am

  • None of these


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235.

If 0 < P(A) < 1, 0 < P(B) < 1 and P(A  B) = P(A) + P(B) - P(A)P(B),then

  • PA  BC = PACPBC

  • P(A/B) = P(A)

  • Both (a) and (b) are  true

  • None of the above


236.

Find the binomial probability distribution whose mean is 3 and variance is 2.

  • 23 + 139

  • 53 + 239

  • 33 + 129

  • None of these


237.

For a binominal variate X, if n = 4 and P(X = 4) = 6P(X = 2), then the value of p is

  • 37

  • 47

  • 67

  • 57


238.

In binomial distribution the probability of getting success is 14 and the standard deviation is 3. Then, its mean is

  • 6

  • 8

  • 10

  • 12


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239.

If the mean of a poisson distribution is 12, then the ratio of P(X = 3) to P(X = 2) is

  • 1 : 2

  • 1 : 4

  • 1 : 6

  • 1 : 8


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240.

A random variable X takes the values 0, 1 and 2. If P(X = 1) = P(X = 2) and P(X = 0) = 0.4, then the mean of the random variable X is

  • 0.2

  • 0.7

  • 0.5

  • 0.9


D.

0.9

We have, PX = 1 = PX = 2        ...iλ1!eλ = λ22!eλ  λ = 2Also, PX = 0 + PX = 1 + PX = 2 = 1 0.4 + PX = 1 +PX = 2 = 1 PX = 1 +PX = 2 = 0.6 = 610 = 35   from Eq.(i)Also, PX = 1 = 310 PX = 1 = PX = 2 = 310Mean X0PX = 0 + X1PX = 1 + X2PX = 2                    = 0 + 0 . 310 + 2 . 310 = 910 = 0.9


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