Function f : N N, f(x) = 2x + 3 is
many-one onto function
many-one into function
one-one onto function
one-one into function
Let R = {(1, 1), (1, 3), (4, 2), (2, 4), (2, 3), (3, 1)} be a relation on the set A = {1, 2, 3, 4}. The relation R is
a function
transitive
not symmetric
reflexive
C.
not symmetric
We have, R = {(1, 1), (1, 3), (4, 2), (2, 4), (2, 3), (3, 1)} is a relation on the set A = {1, 2, 3, 4}, then
(a) Since, (2, 4) and (2, 3) R, so R is not a function
(b) Since, (4, 2) R and (2, 4) R but (4, 4) R so R is not a transitive
(c) Since, (2, 3) R but (3, 2) R, so R is not symmetric
(d) Since, (4, 4), (2, 2), (3, 3) R, so R is not reflexive.
The relation R in R defined by R = {(a, b): a b3), is
reflexive
symmetric
transitive
None of these