If ∑i = 1nxi - a = n and ∑i = 1nxi - a2 = na, n, a1 > 1 then the standard deviation of nobservations x1, x2, ... xn is :
a - 1
na - 1
D.
S.D. = ∑xi2n - ∑xin2= ∑xi - a2n - ∑xi - an2= n . an - na2= a - 1