The point of intersection of the straight lines and is
(- 3, - 4, - 5)
(- 3, 4, 5)
(- 3, 4, - 5)
(3, - 4, 5)
The straight line is parallel to the plane . Then, the distance between the straight line and the plane is
The equation of the plane that passes through the points (1, 0, 2), (-1, 1, 2), (5, 0, 3) is
x + 2y - 4z + 7 = 0
x + 2y - 3z + 7 = 0
x - 2y + 4z + 7 = 0
2y - 4z - 7 + x = 0
A.
x + 2y - 4z + 7 = 0
Equation of the plane passing through (1, 0, 2), (-1, 1, 2), (5, 0, 3) is given by
The equation of the plane passing through the intersection of the planes x + 2y + 3z + 4 = 0 and 4x + 3y + 2z + 1 = 0 and the origin is :
3x + 2y + z + 1 = 0
3x + 2y + z = 0
2x + 3y + z = 0
x + y + z = 0
The equation of the plane passing through (2, 3, 4) and parallel to the plane 5x - 6y + 7z = 3 is :
5x - 6y + 7z + 20 = 0
5x - 6y + 7z - 20 = 0
- 5x + 6y - 7z + 3 = 0
5x + 6y + 7z + 3 = 0