A vector of magnitude 7 units, parallel to the resultant of the vectors a = 2 i - 3j - 2k and b = - i + 2j + k, is
7(i - j - k)
The triangle formed by the three points whose position vectors are 2i + 4j - k, 4i + 5j + k and 3i + 6j - 3k, is
an equilateral triangle
a right angled triangle but not isosceles
an isosceles triangle but not right angled triangle
a right angled isosceles triangle
If (1, 2, 4) and (2, - 3, - 3) are the initial and terminal points of the vector i + 5j - 7k, then the value of is
Let u = 5a + 6b + 7c, v = 7a - 8b + 9c and w = 3 a + 20b + 5c, where a, b and c are non-zero vectors. If u = lv + mw, then the values of l and m respectively are
A.
Given, u = 5a + 6b + 7c
v = 7a - 8b + 9c
and w = 3a + 20b + 5c
Now, u = lv + mw
On comparing, we get
7l + 3m = 5 ...(i)
20m - 8l = 6 ...(ii)
and 5m + 9l = 7 ...(iii)
On multiply by 4 in Eq. (iii) and then subtracting from Eq. (ii), we get
8l - 36l = 6 - 28