a→ × b→2 + a→ .&nbs

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 Multiple Choice QuestionsMultiple Choice Questions

271.

Let a, b and c be vectors with magnitudes 3, 4 and 5 respecnvely and a + b + c = 0, then the values of a . b + b .c + c . a is

  • 47

  • 25

  • 50

  • - 25


272.

A particle is moving in a straight line with uniform velocity. Its acceleration is

  • positive

  • negative

  • zero

  • none of these


273.

If a particle is projected with a velocity 49 m/s making an angle 60° with the horizontal, its time of flight is

  • 103

  • 53

  • 3s

  • none of these


274.

If two equal components (P) of a force (F) are acting at an angle 120°, then F is

  • P

  • P2

  • 2P

  • P2


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275.

The value of a b + c a + b + c is :

  • a b c

  • 0

  • 2a b c

  • a × b × c


276.

The area of the triangle having vertices as i^ - 2j^ + 3k^- 2i^ + 3j^ - k^4i^ - 7j^ + 7k^ is :

  • 36 sq unit

  • 0  sq unit

  • 39 sq unit

  • 11 sq unit


277.

The figure formed by the four points i^ + j^ - k^2i^ + 3j^5j^ - k^ and k^ - j^ is :

  • trapezium

  • rectangle

  • parallelogram

  • None of these


278.

The unit vector perpendicular to i^ - j^ and coplanar with i^ + 2j^ and 2i^ + 3j^ is :

  • 2i^ - 5j^29

  • 2i^ + 5j^

  • i^ + j^2

  • i^ + j^


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279.

a × b2 + a . b2 is equal to :

  • a2 b2

  • a2 + b2

  • 1

  • 2a . b


A.

a2 b2

Given that, a × b2 + a . b2= a b sinθ . n^2 + a b cosθ2           a × b = a b sinθ n^and a . b = a b cosθ= a2 b2 sin2θ + cos2θ= a2 b2     sin2θ + cos2θ = 1


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280.

If a × b2 +a . b2 = 144 and a = 4, then b is equal to

  • 12

  • 3

  • 8

  • 4


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