The de-Broglie wavelength of an electron moving with a velocity c/2 (c = velocity of light in vacuum) is equal to the wavelength of a photon. The ratio of the kinetic energies of electron and photon is
1 : 4
1 : 2
1 : 1
2 : 1
The ionization energy of hydrogen is 13.6 eV. The energy of the photon released when an electron jumps from the first excited state (n = 2) to the ground state of a hydrogen atom is
3.4 eV
4.53 eV
10.2 eV
13.6 eV
The de-Broglie wavelength of an electron is the same as that of a 50 keV X-ray photon. The ratio of the energy of the photon to the kinetic energy of the electron is (the energy equivalent of electron mass is 0.5 MeV)
1 : 50
1 : 20
20 : 1
50 : 1
C.
20 : 1
de-Broglie wavelength
The kinetic energy of the electron
......(i)
where h = Planck Constant
λ = wavelength
The photon energy
.......(ii)
From Eqs. (ii) and (i), we get
Consider two particles of different masses. In which of the following situations the heavier of the two particles will have smaller de-Broglie wavelength ?
Both have a free fall through the same height
Both move with the same kinetic energy
Both move with the same linear momentum
Both move with the same speed