An electric bulb is marked 100 W, 230 V. If the supply voltage dr

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 Multiple Choice QuestionsMultiple Choice Questions

111.

A milliammeter of range 0- 30 mA has internal resistance of 20 Ω. The resistance to be connected in series to convert it into a voltmeter of maximum reading 3V is

  • 49 Ω

  • 80 Ω

  • 40 Ω

  • 30 Ω


112.

In the given circuit the equivalent resistance between the points A and B in ohms is

                      

  • 9

  • 11.6

  • 14.5

  • 21.2


113.

In the electric circuit shown each cell has an emf of 2V and internal resistance of 1Ω. The external resistance is 2Ω. The value of the current I is : (in amperes)

             

  • 2

  • 1.25

  • 0.4

  • 1.2


114.

The radius of the coil of a TG which has 10 turns is 0.1 m. The current required to produce a deflection of 60° (Bh = 4 × 10-5 T) is

  • 3 A

  • 1.1 A

  • 2.1 A

  • 1.5 A


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115.

A 5O mH coil carries a current of 2 A, the energy stored in joule is

  • 1

  • 0.05

  • 0.1

  • 0.5


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116.

An electric bulb is marked 100 W, 230 V. If the supply voltage drops to 115 V, what is the total energy produced by the bulb in 10 min ?

  • 30 kJ

  • 20 kJ

  • 15 kJ

  • 10 kJ


C.

15 kJ

      R = 230 × 230100 = 529 Ω  H = V2R × t         = 115 × 115529 × 10 × 60         = 15 kJ


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117.

In the Wheatstone's bridge shown below, in order to balance the bridge we must have

               

  • R1 = 3 Ω, R2 = 3 Ω

  • R1 = 6 Ω, R2 = 1.5 Ω

  • R1 = 1.5 Ω, R2 = any finite value

  • R1 = 3 Ω, R2 = any finite value


118.

A resistor is constructed as hollow cylinder of dimensions ra = 0.5 cm and rb = 1.0 cm and ρ = 3 .5 x-10-5 Ωm. The resistance of the configuration for the length of 5 cm cylinder is 

  • 7.42 × 10-3 Ω

  • 10.56 × 10-3 Ω

  • 14.38 × 10-3 Ω

  • 16.48 × 10-3 Ω


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119.

The resistances are connected as shown in the figure below. Find the equivalent resistance between the points A and B.

            

  • 205 Ω

  • 10 Ω

  • 3.5 Ω

  • 5 Ω


120.

The figure below shows a 2.0 V potentiometer used for the determination of internal resistance of a 2.5 V cell. The balance point of the cell in the open circuit is 75 cm. When a resistor of 10 Ω is used in the external circuit of the cell, the balance point shifts to 65 cm length of potentiometer wire. Then the internal resistance of the cell is

              

  • 2.5 Ω

  • 2.0 Ω

  • 1.54 Ω

  • 1.0 Ω


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