N identical drops of mercury are charged sumultaneously to 10 V. When combined to form one large drop, the potential is found to be 40 V, the value of N is
4
6
8
10
C.
8
After combining, the volume remains same i.e., volume of bigger drop = N x Volume of smaller drop
or
As charge is conserved, hence
Q = Nq .......... (ii)
Capacity of bigger drop =
Capacity of smaller drop =
From Eq. (ii), we have
From Eqs. (i) and (iii),
The electrostatic potential energy between proton and electron separated by a distance 1 is
13.6 V
27.2 eV
14.4 eV
1.44 eV
The plates of a parallel plate capacitor with air as medium are separated by a distance of 8 mm. A medium of dielectric constant 2 and thickness 4 mm having the same area is introduced between the plates. For the capacitance to remain the same, the distance between the plates is
8 mm
6 mm
10 mm
12 mm
Two identical air core capacitors are connected in series to a voltage source of 15 V. If one of the capacitors is filled with a medium of dielectric constant 4, the new potential across this capacitor is
5 V
8 V
10 V
12 V
A network of six identical capacitors, each of value C, is made as shown in the figure.
The equivalent capacitance between the points A and B is
3C/4
3C/2
3C
Find the potential at the centre of a square of side m which carries at its four corners charges q1 = 3 × 10-6 C, q2 = − 3 × 10-6 C, q3 = − 4 × 10-6 C, q4 = 7 × 10-6 C
2.7 × 104 V
1.5 × 103 V
3 × 102 V
5 × 103 V
If c is the speed of electromagnetic waves in vacuum, its speed in a medium of dielectric constant K and relative permeability μr is
The electrostatic field due to a charged conductor just outside the conductor is
zero and parallel to the surface at every point inside the conductor
zero and is normal to the surface at every point inside the conductor
parallel to the surface at every point and zero inside the conductor
normal to the surface at every point and zero inside the conductor
Figure below shows four plates each of area A and separated from one another by a distance d. What is the capacitance between P and Q ?
A soap bubble is charged to a potential of 16 V. Its radius is, then doubled. The potential of the bubble now will be
16 V
8 V
4 V
2 V