Three capacitors 3 µF, 6 µF and 6 µF are connected in series to a source of 120 V. The potential difference, in volt, across the 3 µF capacitor will be
24
30
40
60
D.
60
The combination of three charges in series
The charge of this circuit
q = CV = 1.5 × 120
q = 180 µC
The potential difference across the 3 µF
A parallel plate capacitor is charged and then disconnected from the charging battery. If the plates are now moved farther apart by pulling at them by means of insulating handles, then
the energy stored in the capacitor decreases
the capacitance of the capacitor increases
the charge on the capacitor decreases
the voltage across the capacitor increases
Half of the space between the plates of a parallel-plate capacitor is filled with a dielectric material of dielectric constant K. The remaining half contains air as shown in the figure. The capacitor is now given a charge Q. Then
electric field in the dielectric-filled region is higher than that in the air-filled region.
on the two halves of the bottom plate the charge densities are unequal.
charge on the half of the top plate above the air-filled pant is
capacitance of the capacitor shown above is , where C0 is the capacitance of the same capacitor with the dielectric removed.
A 5 µF capacitor is connected in series with a 10 µF capacitor. When a 300 V potential difference is applied across this combination, the total energy stored in the capacitors is
15 J
1.5 J
0.15 J
0.10 J