Two soap bubbles of radii x and y coalesce to constitute a bubble

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 Multiple Choice QuestionsMultiple Choice Questions

211.

A body floats in water with 40% of its volume outside water. When the same body floats in oil, 60% of its volume remains outside oil. The relative density of the oil is

  • 0.9

  • 1.2

  • 1.5

  • 1.8


212.

A uniform long tube is bent into a circle of radius R and it lies in vertical plane. Two liquids of same volume but densities ρ and δ fill half the tube. The angle θ is

      

  • tan-1 ρ - δρ + δ

  • tan-1 ρδ

  • tan-1 δρ

  • tan-1 ρ + δρ - δ


213.

Two solid spheres of same metal but of mass M and 8M fall simultaneously on a viscous liquid and their terminal velocities are v and nv, then value of n is

  • 16

  • 8

  • 4

  • 2


214.

A stone of relative density K is released from rest on the surface ofa lake. If viscous effects are ignored, the stone sinks in water with an acceleration of

  • g (1 − K)

  • g (1 + K)

  • g 1 - 1K

  • g 1 + 1K


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215.

An object weights m1 in a liquid of density d1 and that in liquid of density d2 is m2. The density d of the object is

  • m2d2 - m1d1m2 - m1

  • m1d1 - m2d2m2 - m1

  • m2d1 - m1d2m1 - m2

  • m1d2 - m2d1m1 - m2


216.

A body floats in water with 40% of its volume outside water. When the same body floats in an oil. 60% of its volume remains outside oil. The relative density of oil is

  • 0.9

  • 1.0

  • 1.2

  • 1.5


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217.

Two soap bubbles of radii x and y coalesce to constitute a bubble of radius z. Then z is equal to 

  • x2 + y2

  • x + y

  • x + y

  • x + y2


A.

x2 + y2

Given that two soap bubbles coalesce to constitute a bubble of radius z. Now from the ideal gas law, we get

            pV = p1V1 + p2V2

Hence, we have,

          nRT = n1RT + n2RT

So,         n = n1 + n2

Thus, we have 

p1 = p0 + 4Tx , p2 = p0 + 4Ty , p = p0 + 4Tz

Assuming that the process is taking place in vacuum, we have

p1 = 4Tx , p2 = 4Ty , p = 4TzHence, pV = p1V1 + p2V2or 4Tz 43πz3 = 4Tx 43πx3 + 4Ty 43 πy3Hence,  z2 = x2 + y2   z = x2 + y2


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218.

Air inside a closed container is saturated with water vapour. The air pressure is p and the saturated vapour pressure of water is p¯. If the mixture is compressed to one-half of its volume by maintammg temperature constant, the pressure becomes

  • 2p + p¯

  • 2p + p¯

  • p + p¯/2

  • p + 2p¯


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219.

A diver at a depth of 12 m in water μ = 43 sees the sky in a cone-of semivertical angle

  • sin-143

  • tan-143

  • sin-134

  • 90°


220.

Water is flowing through a very narrow tube. The velocity of water below which the flow remains a streamline flow is known as

  • relative velocity

  • terminal velocity

  • critical velocity

  • particle velocity


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