A ball dropped from a point A falls down vertically to C, through

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 Multiple Choice QuestionsMultiple Choice Questions

11.

The x-t plot shown in the figure below describes the motion of the particle, along x-axis, between two positions A and B. The particle passes through two intermediate points P1 and P2 as shown in the figure

       

  • The instantaneous velocity is positive as P1 and negative at P2.

  • The instantaneous velocity is negative at both P1 and P2

  • The instantaneous velocity is negative at P1 and positive at P2

  • The instantaneous velocity is positive at both P1 and P2


12.

The graph which cannot possibly represent one-dimensional motion is


13.

A man rides a bicycle with a speed of 17.32 ms-1 East- West direction. If the rain falls vertically with a speed of 10 ms-1, then the direction in which he must hold his umbrella is

  • 30° with the vertical towards East

  • 60° with the vertical towards West

  • 30° with the vertical towards West

  • 60° with the vertical towards East


14.

From a balloon moving upwards with a velocity of12 ms-1, a packet is released when it is at a height of 65 m from the ground. The time taken by it to reach the ground is (take, g = 10 ms-2)

  • 5 s

  • 8 s

  • 4 s

  • 7 s


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15.

A bus is moving with a velocity of 10 ms-1 on a straight road. A scootorist wishes to overtake the bus in one minute. If the bus is at a distance of 1.2 km ahead, then the velocity with which he has to chase the bus is

  • 20 ms-1

  • 25 ms-1

  • 30 ms-1

  • 40 ms-1


16.

If the displacement of a body varies as the square of elapsed time, then its

  • velocity is constant

  • velocity varies non-uniformly

  • acceleration is constant

  • acceleration changes continuously


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17.

A ball dropped from a point A falls down vertically to C, through the mid-point B. The descending time from A to B and that from A to C are in the ratio

  • 1 : 1

  • 1 : 2

  • 1 : 3

  • 1 : 2


D.

1 : 2

Let the distance between point A and B is s
As, u = O, then

We know that, s = ut + 12 gt2

For point A to B, s = 12 gt2            ......... (i)

For point A to C, 2s = 12 gt2         ......... (ii)

On dividing Eq. (ii) by Eq. (i), we get

t2t'2 = 12   tt' = 12 = 1 : 2


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18.

The time required to stop a car of mass 800 kg, moving at a speed of 20ms-1 over a distance of 25 m is

  • 2 s

  • 2.5 s

  • 4 s

  • 4.5 s


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19.

For a particle moving according to the equation x = a cos π t, the displacement in 3 s is

  • 0

  • 0.5 a

  • 1.5 a

  • 2 a


20.

The ratio of distance traversed in successive intervals of time when a body falls freely under gravity from certain height is

  • 1 : 2 : 3

  • 1 : 5 : 9

  • 1 : 3 : 5

  • 1 : 2 : 3


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