A man of height h walks in a straight path towards a lamp post of

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 Multiple Choice QuestionsMultiple Choice Questions

51.

A boat travels 50 km east, then 120 km North and finally it comes back to the starting point through the shortest distance. The total time of journey is 3 h. What is the average velocity, in km h-1 over the entire trip ?

  • zero

  • 100

  • 17

  • 33.33


52.

A toy cyclist completes one round of a square track of side 2 m in 40 s. What will be the displacement at the end of 3 min ?

  • 52 m

  • zero

  • 16 m

  • 22 m


53.

Two trains, each of length 200 m are runmng on parallel tracks. One overtakes the other in 20 s and one crosses the other in 10 s. The velocities of the two trains are

  • 5 m/s, 10 m/s

  • 10 m/s, 30 m/s

  • 15 m/s, 5 m/s

  • 20 m/s, 21 m/s


54.

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th second to that covered in 5 s is

  • 925

  • 35

  • 255

  • 125


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55.

The area under acceleration-time graph gives

  • distance travelled

  • change in acceleration

  • force acting

  • change in velocity


56.

Two masses M and M/2 are joined together by means of light inextensible string passed over a frictionless pulley as shown in the figure. When the bigger mass is released, the small one will ascend with an acceleration of

                        

  • g3

  • 3g2

  • g2

  • g


57.

The recoil velocity of a 4.0 kg rifle that shoots a 0.050 kg bullet at a speed of 280 ms-1 is

  • + 3.5 ms-1

  • − 3.5 ms-1

  • - 3.5 ms-1

  • + 3.5 ms-1


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58.

A man of height h walks in a straight path towards a lamp post of height H with uniform velocity u. Then the velocity of the edge of the shadow on the ground will be

  • huH - h

  • HuH + h

  • H - hHu

  • H + hHu


A.

huH - h

Let in same time t, distance covered by man and edge of image be respectively x and y                            tan θ = H - hx = Hx + y  Hx = Hx + Hy - hx + hy

            

         xy = H - hh                               ...... (i)Now,       x = utand         y = vt         xy = uv                                        ....... (ii)Hence,  uv = H - hh          v = huH - h


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59.

A train of 150 m length is going towards north direction at a speed of 10 ms-1. A parrot flies at a speed of 5 ms-1 towards south direction parallel to the railway track. The time taken by the parrot to cross the train is equal to

  • 12 s

  • 8 s

  • 15 s

  • 10 s


60.

An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically above a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

  • 1200 m

  • 0.33 km

  • 3.33 km

  • 33 km


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