A galvanometer of resistance 50 Ω gives a full scale deflection for a current 5 x 10-4 A. The resistance that should be connected in series with the galvanometer to read 3 V is
5059 Ω
595 Ω
5950 Ω
5050 Ω
A cyclotron is used to accelerate
only negatively charged particles
neutron
both positively and negatively charged particles
only positively charged particles
A proton is projected with a uniform velocity v along the axis of a current-carrying solenoid, then
the proton will be accelerated along the axis
the proton path will be circular about the axis
the proton move along helical path
the proton will continue to move with velocity v along the axis
In the cyclotron, as radius of the circular path of the charged particle increases (ω = angular velocity, v = linear velocity)
both ω and v increase
ω only increases, v remains constant
v increases, ω remains constant
v increases, ω decreases
A conducting wire carrying current is arranged as shown in the figure. The magnetic field at O is
A galvanometer coil has a resistance of 50 Ω and the meter shows full scale deflection for a current of 5 mA. This galvanometer is converted into voltmeter of range 0-20 V by connecting
3950 Ω in series with galvanometer
4050 Ω in series with galvanometer
3950 Ω in parallel with galvanometer
4050 Ω in parallel with galvanometer
A long solenoid with 40 turns per cm carries a current of 1 A. The magnetic energy stored per unit volume is
A proton, a deuteron and an α-particle are projected perpendicular to the direction of a uniform magnetic field with same kinetic energy. The ratio of the radii of the circular paths described by them is
A galvanometer of resistance 50 Ω is connected to a battery of 3 V along with. a resistance of 2950 Ω in series shows full-scale deflection of 30 divisions. The additional series resistance required to reduce the deflection to 20 divisions is
2950 Ω
1500 Ω
4450 Ω
7400 Ω
A magnetic dipole of magnetic moment 6 × 10-2 A-m2 and moment of inertia 12 x 10-6 kg-m2 performs oscillations in a magnetic field of 2 x 10-2 T. The time taken by the dipole to complete 20 oscillations is (π ≈ 3)
18 s
6 s
36 s
12 s
D.
12 s
Given,
Magnetic moment (M) = 6 × 10-2 A-m2
Moment of inertia (I) = 12 × 10-6 kg-m2
Magnetic field (B) = 2 × 10-2 T
We know that,