A speeding motorcyclist sees traffic jam ahead of him. He slows down to 36 km/hr. He finds that traffic has eased and a car moving ahead of him at 18 km/hr is honking at a frequency of 1392 Hz. If the speed of sound is 343 m/s, the frequency of the honk as heard by him will be,
1332 Hz
1372 Hz
1412 Hz
1412 Hz
Two waves are represented by the equations, m where x is in metre and t in second. The phase difference between them is
1.25 rad
1.57 rad
0.57 rad
0.57 rad
Sound waves travel at 350 m/s through a warm air and at 3500 m/s through brass. The wavelength of a 700 Hz acoustic wave as it enters brass from warm air.
increases by a factor 20
increases by a factor 10
decreases by a factor 20
decreases by a factor 20
Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively illuminate a metallic surface whose work function is 0.5 eV successively. Ratio of maximum speeds of emitted electrons will be
1:2
1:4
1:5
1:5
A source of sound S emitting waves of frequency 100 Hz and an observer O are located at some distance from each other. The source is moving with a speed of 19.4 ms-1 at an angle of 60o with the source observer is at rest. the apparent frequency observed by the observer (velocity of sound in air 330 ms-1) is
100 Hz
103 Hz
106 Hz
106 Hz
A transverse wave os represented by y = A sin (ωt - kx). For what value of the wavelength is the wave velocity equal to the maximum particle velocity?
π A /2
π A
2πA
2πA
A tuning fork of frequency 512 Hz makes 4 beats/s with the vibrating string of a piano. The beat frequency decreases to 2 beats/s when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was.
510 Hz
514 Hz
516 Hz
516 Hz
A wave in a string has an amplitude of 2 cm. The wave travels in the +ve direction of x -axis with a speed of 128 ms-1 and it is noted that 5 complete waves fit in 4 m length of the string. The equation describing the wave is
y = (0.02) m sin (7.85 x +1005t)
y = (0.02) m sin (15.7 x -2010t)
y = (0.02) m sin (15.7 x + 2010t)
y = (0.02) m sin (15.7 x + 2010t)
The driver of a car travelling with speed 30 ms-1 towards a hill sounds a horn of frequency 600 Hz. If the velocity of sound in air is 330 ms-1, the frequency of reflected sound as heard by driver is
550 Hz
555.5 Hz
720 Hz
720 Hz
The wave described by y = 0.25 sin (10 π x -2 πt), where x and y are in metre and t in second, is a wave travelling along the
- ve x direction with frequency 1 Hz
+ve x direction with frequency π Hz and wavelength λ = 0.2 m
+ve x direction with frequency 1 Hz and wavelength λ = 0.2 m
+ve x direction with frequency 1 Hz and wavelength λ = 0.2 m
C.
+ve x direction with frequency 1 Hz and wavelength λ = 0.2 m
The sign between two terms in the argument of sine will define its direction.
Writing the given wave equation
y= 0.25 sin (10 πx- 2πt) ... (i)
The minus (-) between (10πx) and (2πt) implies that the waves is travelling along the positive x-direction.
Now comparing eq (i) with standard wave equation
y = a sin (kx -ωt) ..... (ii)
we have
a= 0.25m, ω = 2π, k = 10 π m
therefore,
2π/T = 2π
f= 1Hz
λ = 2π/k = 2π/10π = 0.2 m
Therefore, the wave is travelling along +ve x direction wth frequency 1 Hz and wavelength 0.2m