A haemophilic woman marries a normal man then from Biology Princ

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 Multiple Choice QuestionsMultiple Choice Questions

111.

A man and a woman, who do not show any apparent signs of a certain inherited disease, have seven children (2 daughters and 5 sons). Three of the sons suffer from the given disease but none of the daughters are affected. Which of the following mode of inheritance do you suggest for this disease?

  • Autosomal dominant

  • Sex-linked dominant

  • Sex-limited recessive

  • Sex-linked recessive


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112.

A haemophilic woman marries a normal man then

  • all the children will be normal

  • all the sons will be haemophilic

  • all the girls will be haemophilic

  • half girls will be haemophilic


B.

all the sons will be haemophilic

Haemophilia is x linked recessive trait (where females are the carrier) in which a person lacks certain clotting factors which don't let the blood to clot properly. 


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113.

A woman with normal vision, but whose father was colourblind, marries a colourblind man. Suppose that the fourth child of this couple was a boy. This boy

  • must have normal colour vision

  • will be partially colourblind since he is heterozygous for the colourblind mutant allele

  • must be colourblind

  • may be colourblind or may be of normal vision


114.

Husband has blood group A and wife has blood group B. What is the blood group of children

  • A

  • B

  • AB

  • A, B, AB or 0


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115.

Which of the following is not a hereditary disease?

  • Cretinism

  • Cystic fibrosis

  • Thalassaemia

  • Haemophilia


116.

de Vries gave his mutation theory on organic evolution while working on

  • Althea rosea

  • Drosophila melanogaster

  • Oenothera lamarckiana

  • Pisum sativum


117.

A woman with 47 chromosomes due to three copies of chromosome 21 is characterized by

  • Down syndrome

  • triploidy

  • Turner syndrome

  • super femaleness


118.

Kappa particles indicate

  • nuclear inheritance

  • cytoplasmic inheritance

  • mutation

  • nucleo-cytoplasmic inheritance


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119.

Using imprints from a plate with complete medium and carrying bacterial colonies, you can select streptomycin resistant mutants and prove that such mutations do not originate as adaptation. These imprints need to be used

  • only on plates with streptomycin

  • on plates with minimal medium

  • only on plates without streptomycin

  • on plates with and without streptomycin


120.

In order to find out the different types of gametes produced by a pea plant having the genotype AaBb, it should be crossed to a plant with the genotype

  • aaBB

  • AaBb

  • AABB

  • aabb


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