The correct sequence of base strengths in aqueous solution is :
(CH3)2NH > CH3NH2 > (CH3)3N
(CH3)3N > CH3NH2 >(CH3)2NH
(CH3)3N > CH3NH2 = (CH3)2NH
(CH3)2NH > (CH3)3N > CH3NH2
When aqueous solution of benzene diazoniumchloride is boiled, the product formed is:
C6H5CH2OH
C6H6 + N2
C6H5COOH
C6H5OH
Carbylamine reaction is given by aliphatic :
primary amine
secondary amine
tertiary amine
quaternary ammonium salt
An organic compound 'A' having molecular formula C2H3N on reduction gave another compound B, upon treatment with nitrous acid 'B' gave ethyl alcohol. On warming with chloroform and alcoholic KOH, it formed an offensive smelling compound 'C'. The compound 'C' is
CH3CH2NH2
CH3CH2N C
CH3C
CH3CH2.OH
Compound (A) (molecular formula C3H8O) is treated with acidified potassium dichromate to form a product B (molecular formula C3H6O). 'B' forms a shining silver mirror on warming with ammoniacal silver nitrate. 'B' when treated with an aqueous solution of H2NCONHNH2 · HCl and sodium acetate gives a product C'. Identify the structure of 'C
The decreasing order of basic characters of the three amines and ammonia is
NH3 > CH3NH2 > C2H5NH2 > C6H5NH2
C2H5NH2 > CH3NH2 > NH3 > C6H5NH2
C6H5NH2 > C2H5NH2 > CH3NH2 > NH3
CH3NH2 > C2H5NH2 > C6H5NH2 > NH3
Benzene diazonium chloride on treatment with hypo phosphorus acid and water in presence of Cu+ catalyst produce
benzene
toluene
aniline
chlorobenzene
Which of the following reagents will be fruitful for separating a mixture of nitrobenzene and aniline?
aq. NaHCO3
H2O
aq. HCl
aq. NaOH
C.
aq. HCl
Key Idea: The reagent selected should be such that only one of components to be separated, reacts with it.
Therefore, aq. HCl is used to separate aniline and nitrobenzene.