The central carbon atom of a free radical contains
6 electrons
7 electrons
8 electrons
10 electrons
Reaction for the formation of NaCl is
Na(g) + Cl2(g) → NaCl(s)
Na(s) + Cl2(g) → NaCl(s)
Na(g) + Cl2(g) → NaCl(s)
Na(g) + Cl2(g) → NaCl(g)
Which of the following has least bond energy?
N
N
N
N2
D.
N2
i. N - KK' σ2s2, σ*2s2, σ2p, 2p ≈ 2p, *2p
Bond Order = = = 2
ii. N - KK' σ2s2, σ*2s2, σ2p, 2p ≈ 2p, *2p
Bond Order = = 2.5
iii. N - KK' σ2s2, σ*2s2, σ2p,
Bond Order = = 3
iv. N2 - KK' σ2s2, σ*2s2,
Bond Order = = 3
Bond energy
Therefore, N2 has least bond energy.