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 Multiple Choice QuestionsMultiple Choice Questions

471.

The dipole moment of HBr is 2.60 x 10-30 Cm and the interatomic spacing is 1.41 A .The percent ionic character of HBr is:

  • 11.5%

  • 10.1%

  • 8.2%

  • 4.1%


472.

Which of the following gives correct arrangement of compounds involved based on their bond strength ?

  • HF > HCl > HBr > HI

  • HI > HBr > HCl > HF

  • HF > HBr > HCl > HI

  • HCl > HF > HBr > HI


473.

H-bond is strongest in

  • C2H5OH

  • H-F

  • H2O

  • CH3COCH3


474.

Hybridization of 1 and 2 carbon atom in

C1H2C2 = CHare

  • sp, sp

  • sp2, sp2

  • sp2, sp

  • sp3, sp2


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475.

The hybridisation and shape of IF5 are respectively:

  • sp3d , trigonal bipyramide

  • sp3d , see saw

  • sp3d , square pyramidal

  • sp3d , pentagonal pyramidal


476.

Number of orbitals in L energy level

  • 1

  • 2

  • 3

  • 4


477.

Assuming that Hund's rule in violated,the bond order and magnetic nature of the  diatomic molecule B2 is:

  • 1 and diamagnetic

  • 0 and diamagnetic

  • 1 and paramagnetic

  • O and paramagnetic


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478.

Using MO theory, predict which of the following species has the shortest bond length?

  • O22+

  • O2+

  • O2-

  • O22-


A.

O22+

MO configuration for O2 is σ1s2σ*1s2σ2s2σ*2s2σ2pz2 ,π2px2  π2py2 , π*2px1  π*2py1

Thus bond order 12 (10-6) = 2 of O2

Bond order of O210 - 42 = 3

Bond order of O2+ = 10 - 52 = 2.5

                    O2- = 10 - 72 = 1.5

                   O22- = 10 - 82 = 1

Since bond order in inversely related to bond length, O22+ with the highest bond order of 3 has the shortest bond length.


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479.

The shape of an orbital is determined by

  • n

  • l

  • m

  • s


480.

The enthalpies of all elements in their standard states are

  • zero

  • >0

  • <0

  • unity


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