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 Multiple Choice QuestionsMultiple Choice Questions

611.

The correct order of decreasing length of the bond as indicated by the arrow in the following structures is

  • I > II > III

  • II > I > III

  • III > II > I

  • I > III > II


612.

In case of heteronuclear diatomics of the type AB, where A is more electronegative than B, bonding molecular orbital resembles the character of A more than that of B. The statement 

  • is false

  • is true

  • cannot be evaluated since data is not sufficient

  • is true only for certain systems


613.

Dipole-induced dipole interactions are present in which of the following pairs?

  • H2O and alcohol

  • Cl2 and CCl4

  • HCl and He atoms

  • SiF4 and He atoms


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614.

Which of  the following structure is similar to graphite?

  • CO

  • O2-

  • CN-

  • NO+


B.

O2-

Paramagnetic species contains unpaired electrons in their molecular orbital electronic configuration.
Molecular orbital configuration of the given species is as

  CO(6+8 =14)                      =σ1s2,σ*1s2, σ2s2, σ*2s2, π2px2  π2py2, σ2pz2 

(All the electrons are paired so it is diamagneitc.)

 O2-(8+8+1=17)       = σ1s2, σ*1s2, σ2s2,σ*2s2,σ2pz2, π2px2,  π2py2,π*2px2π*2py1

It contains one unpaired electron so it is paramagnetic.
CN- (6+ 74 1= 14)= same as CO
NO+ (7+ 8- 1)= same as CO
Thus, among the given species only O2- is paramagnetic.


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615.

The bond angle in NF3 (102.3°) is, smaller than NH3 (107.2°). This is because of

  • large size of F compared to H

  • large size of N compared to F

  • opposite polarity of N in the two molecules

  • small size of H compared to N


616.

The structure of XeF6 is experimentally determined to be distorted octahedron. Its structure according to VSEPR theory is

  • octahedron

  • trigonal bipyramid

  • pentagonal bipyramid

  • tetragonal bipyramid


617.

XeF2 is isostructural with

  • TeF2

  • ICl2-

  • SbCl3

  • BaCl2


618.

In the following electron-dot structure calculate the formal charge from left to right nitrogen atom; N....=N=N.... :

  • -1 , -1 , +1

  • -1 , +1 , -1

  • +1 , -1 , -1

  • +1 , -1 , +1


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619.

The sp3d2 hybridisation of central atom of a molecule would lead to:

  • square planar geometry

  • tetrahedral geometry

  • trigonal bipyramidal geometry

  • octahedral geometry


620.

Which one of the following molecules contain no π-bond?

  • CO2

  • H2O

  • SO2

  • NO2


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