Energy of activation of forward reaction for an endothermic proce

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 Multiple Choice QuestionsMultiple Choice Questions

351.

A reaction , 2A  products (x) is found to follow zero order kinetics .Then :

  • dxdt= k [A]

  • dxdt=k [A]0

  • dxdt = k [A]2

  • dxdt = k [2A]


352.

The rate of a reaction is primarily determined by the slowest step .This step is called :

  • rate determining step

  • reaction rate

  • activation step

  • None of the above


353.

For a reaction, r= k(CH3COCH3)3/2 then unit of rate of reaction and rate constant respectively is

  • mol L-1 s-1, mol-1/2 L1/2 s-1

  • mol-1 L-1 s-1, mol-1/2 L-1/2 s-1

  • mol L-1 s-1 mol+1/2L1/2s-1

  • mol L s, mol+1/2 L 1/2 s


354.

If t1/2  vs  1a2 is a straight line graph then determine the order of reaction.

  • Zero order

  • First order

  • Second order

  • Third order


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355.

Energy of activation of forward reaction for an endothermic process is 50 kJ. If enthalpy change for forward reaction is 20 kJ then enthalpy change for backward reaction will be

  • 30 kJ

  • 20 kJ

  • 70 kJ

  • 50 kJ


A.

30 kJ

For endothermic reaction,

Ea,b = Ea,fH°

       = 50 kJ - 20 kJ = 30 kJ


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356.

Assertion : Rate of reaction doubles when concentration of reactant is doubled if it is a first order reaction.

Reason : Rate constant also doubles.

  • If both assertion and reason are true and reason is the correct explanation of assertion.

  • If both assertion and reason are true but reason is not the correct explanation of assertion.

  • If assertion is true but reason is false.

  • If both assertion and reason are false.


357.

A radioactive substance decays 34th of it original value in 2h. The half-life of the substance is :

  • 1 h

  • 30 min

  • 20 min

  • 15 min


358.

The chemical reaction 2O3 3O2 proceeds as :

(I) O3  O2 + O (fast)

(II) O + O3  2O2 (slow)

The rate expression should be :

  • r = k[O3]2

  • r = k[O3]2 [O2]-1

  • r = k[O3] [O2]

  • None of these


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359.

For a 1st order reaction if concentration is doubled then rate of reaction becomes

  • doubles

  • half

  • four times

  • remains same


360.

The first order rate constant for dissociation of N2O5 is 6.2 x 10-4 s-1 .The half-life period (in s) of this dissociation will be :

  • 1117.7

  • 111.7

  • 223.4

  • 160.9


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