Consider the following relations for emf of an electrochemical c

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

261.

Standard electrode potential for Sn4+ / Sn2+ couple is +0.15 V and that for the Cr3+/Cr  couple is -0.74. These two couples in their standard state are connected to make a cell. The cell potential will be

  • +0.89 V

  • +0.18 V

  • +1.83 V

  • +1.83 V

1028 Views

262.

A solution contains Fe2+ Fe3+, and I- ions. This solution was treated with iodine at 35o C.Eo for Fe3+/ Fe2+ is +0.77 V and Eo for I2/ 2 I- = 0.536 V. The favourable redox reaction is 

  • I2 will be reduced to I-

  • There will be No redox reaction

  • I- will be oxidised to I2

  • I- will be oxidised to I2

620 Views

263.

In qualitative analysis, the metals of group I can be separted from other ions by precipitating them as chloride salts. A solution initially contains Ag+ and Pb2+ at a concentration of 0.10 M. Aqueous HCl is added to this solution until the Cl- concentration is 0.10 M. What will be the concentration of Ag+ and Pb2+ be at equilibrium? (Ksp for AgCl = 1.8 x 10-10, Ksp for PbCl2  = 1.7 x 10-5)

  • [Ag+]  = 1.8 x 10-7 M; [Pb2+] = 1.7 x 10-6 M

  • [Ag+]  = 1.8 x 10-11 M; [Pb2+] = 8.5 x 10-5 M

  • [Ag+]  = 1.8 x 10-9 M; [Pb2+] = 1.7 x 10-3 M

  • [Ag+]  = 1.8 x 10-9 M; [Pb2+] = 1.7 x 10-3 M

382 Views

264.

For the reaction of silver ions with copper metal, the standard cell potential was found to be +0.46 V at 25o C. The value of standard Gibbs energy, ΔGo will be (F = 96500 C mol-1

  • -89.0 kJ

  • -89.0 J

  • -44.5 kJ

  • -44.5 kJ

420 Views

Advertisement
265.

An increase in equivalent conductance of strong electrolyte with dilution is mainly due to

  • the increase in ionic mobility of ions

  • 100% ionisation of electrolyte at normal dilution

  • the increase in both, ie, the number of ions and ionic mobility of ions

  • the increase in both, ie, the number of ions and ionic mobility of ions

755 Views

266.

Which of the following expression correctly represents the equivalent conductance at infinite dilution of Al2(SO4)3. Given that straight capital lambda subscript Al to the power of 3 plus end exponent end subscript superscript straight o space and space space straight capital lambda subscript SO subscript 4 superscript 2 minus end superscript end subscript superscript straight oare the equivalent conductance at infinite dilution of the respective ions.

  • 2 straight capital lambda subscript Al to the power of 3 plus end exponent end subscript superscript straight o plus space 3 straight capital lambda subscript SO subscript 4 superscript 2 minus end superscript end subscript superscript straight o
  • straight capital lambda subscript Al to the power of 3 plus end exponent end subscript superscript straight o space plus space space straight capital lambda subscript SO subscript 4 superscript 2 minus end superscript end subscript superscript straight o
  • left parenthesis straight capital lambda subscript Al to the power of 3 plus end exponent end subscript superscript straight o space and space space straight capital lambda subscript SO subscript 4 superscript 2 minus end superscript end subscript superscript straight o right parenthesis space straight x space space 6
  • left parenthesis straight capital lambda subscript Al to the power of 3 plus end exponent end subscript superscript straight o space and space space straight capital lambda subscript SO subscript 4 superscript 2 minus end superscript end subscript superscript straight o right parenthesis space straight x space space 6
1325 Views

Advertisement

267.

Consider the following relations for emf of an electrochemical cell

A) Emf of cell = (oxidation potential of anode) - (reduction potential of cathode)

B) Emf of cell = (oxidation potential of anode) - ( reducation potential of cathode)

C) Emf of cell = (oxidation potential of anode)- (reduction potential of cathode)

D) Emf of cell = (oxidation potential of anode) - (oxidation potential of anode)-(oxidation potential  of cathode)

  • (C) and (A)

  • (A) and (B)

  • (C) and (D)

  • (C) and (D)


D.

(C) and (D)

444 Views

Advertisement
268.

For vaporisation of water at 1 atm pressure, the values of ΔH and ΔS are 40.63 kJ mol- and 108.8 JK-1 mol-1, respectively. The temperature when Gibbs energy change (ΔG) for this transformation will be zero, is

  • 273.14 K

  • 393.4 K 

  • 373.4 K 

  • 373.4 K 

411 Views

Advertisement
269.

Al2O3 is reduced by electrolysis at low potentials and high currents. If 4.5 x 104 An of current is passed through molten Al2O3 for 6h, what mass of aluminium is produced? (Assume 100% current efficiency, at.mass of Al = 27 g mol-1)

  • 9.0 x 103 g

  • 8.1 x 104 g

  • 2.4 x 105

  • 2.4 x 105

1380 Views

270.

The equivalent conductance of M/32 solution of weak monobasic acid is 8.0 ohm-cm2 and at infinite dilution is 400 ohm-cm2. The dissociation constant of this acid is

  • 1.25 x 10-5

  • 1.25 x 10-6

  • 6.25 x 10-4

  • 6.25 x 10-4

1441 Views

Advertisement