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 Multiple Choice QuestionsMultiple Choice Questions

331.

1 dm3 solution containing 10-5 moles each of Cl- ions and CrO42- ions is treated with 10-4 moles of silver nitrate. Which one of the following observations is made?

[KspAg2CrO4 = 4 × 10-12] and [KspAgCl = 1 × 10-10

  • Precipitation does not occur

  • Silver chromate gets precipitated first

  • Silver chloride gets precipitated first

  • Both silver chromate and silver chloride start precipitating simultaneously


332.

pH value of which one of the following is not equal to one?

  • 0.1 M HNO3

  • 0.05 M H2SO4

  • 0.1 M CH3COOH

  • 50 cm3 of 0.4 M HCl + 50 cm3of 0.2 M NaOH


333.

The yield of the products in the reaction A2(g) + 2B(g) C(g) + kJ would be higher at

  • high temperature and high pressure

  • high temperature and low pressure

  • low temperature and high pressure

  • low temperature and low pressure


334.

The equilibrium constant of a reaction is 0.008 at 298 K. The standard free energy change of the reaction at the same temperature is

  • -11.96 kJ

  • -5.43 kJ

  • -8.46 kJ

  • +11.96 kJ


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335.

5 mL of 0.4 N NaOH is mixed with 20 mL of 0.1 N HCl.The pH of the resulting solution will be

  • 7

  • 8

  • 5

  • 6


336.

The pH of the solution obtained by mixing 100 ml of a solution of pH = 3 with 400 mL of a solution of pH = 4 is

  • 7 - log 2.8

  • 4 - log 2.8

  • 5 - log 2.8

  • 3 - log 2.8


337.

The equilibrium constant of the reaction

A (s) + 2B2+ (aq)  A2+ (aq) + 2B (s);

Ecell° = 0.0295 Vis 2.303 RTF = 0.059

  • 2 × 102

  • 3 × 102

  • 2 × 105

  • 10


338.

An example for a neutral buffer is

  • ammonium hydroxide and ammonium chloride

  • acetic acid and sodium acetate

  • acetic acid and ammonium hydroxide

  • citric acid and sodium citrate


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339.

Conjugate base of H2PO42-

  • H3PO4-

  • HPO42-

  • H3PO4

  • PO43-


B.

HPO42-

A conjugate pair of acid and a base differs by a proton only, ie ,

Conjugate acid Conjugate base + H+H2PO4- HPO42- + H+Thus H2PO4- can give a proton & hence is an acid while  HPO42-can accept the proton & hence is a base. 


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340.

For Cr2O72- + 14 H+ + 6e- → 2Cr3+ + 7H2O; E° = 1.33 V. At [Cr2O72-] = 4.5 millimole, [Cr3+] = 15 millimole, E is 1.067 V. The pH of the solution is nearly equal to

  • 2

  • 3

  • 5

  • 4


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