Multiple Choice QuestionsHow many moles of O2 can be obtained by electrolysis of 90 g H2O?
5.0 mol
0.5 mol
2.5 mol
0.25 mol
An organic compound A contains 20% C, 46.66% N and 6.66% H. It gives NH3 gas on heating with NaOH. A can be
CH3CONH2
C6H5CONH2
NH2CONH2
CH3NHCONH2
The empirical formula of a compound is CH2. One mole of this compound has a mass 42g. Its molecular formula is
C3H6
C2H6
CH2
C2H2
Aqueous solutions of hydrogen sulphide and sulphur dioxide when mixed together, yield
sulphur trioxide and water
hydrogen and sulphurous acid
sulphur and water
hydrogen peroxide and sulphur
3 g of oxide of a metal is converted to chloride completely and it yielded 5 g of chloride. The equivalent weight of metal is
12
20
33.25
2.325
4.9 g of H2SO4 is present in 100 mL solution. The molarity and normality of the solution will be
Molarity = 1M, Normality= 0.5N
Molarity = 1M, Normality= 0.25N
Molarity = 0.5M, Normality= 1N
Molarity = 2M, Normality= 3N
0.0833 mole of a carbohydrate of empirical formula CH2O contains 1.00 g of hydrogen. The molecular formula of the carbohydrate is.
C5H10O5
C3H4O3
C12H22O11
C6H12O6
When 50cm3 of 0.2N H2SO4 is mixed with 50 cm3 of 1N KOH, the heat liberated is
11.46 kJ
57.3 kJ
573 kJ
573 J
D.
573 J
The number of gram-equivalents of
We know that 57.3 kJ heat is evolved when one gram-equivalent of strong acid (like H2SO4) and one gram-equivalent of strong base (like KOH) are neutralised. Here 1.0 × 10-2 gram- equivalent of H2SO4 is neutralised by 1.0 × 10-2 gram- equivqlent of KOH hence the heat evolved will be
= 57.3 kJ × 1.0 × 10-2
= 57.3 × 103× 10-2J
= 573 J
Heat liberated with 100 mL of 1 N NaOH is neutralised by 300 mL of 1 N HCl
11.56 kJ
5.73 kJ
22.92 kJ
17.19 kJ
A solution contains 1.2046 x 1024 hydrochloric acid molecules in one dm3 of the solution. The strength of the solution is
6N
2N
4N
8N
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