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 Multiple Choice QuestionsMultiple Choice Questions

221.

What amount of bromine will be required to convert 2 g of phenol into 2, 4, 6-bribromo phenol?

  • 20.44 gm

  • 6.00 gm

  • 4.00 gm

  • 10.22 gm


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222.

The concentration of H2O2 solution of 10 volume is

  • 30%

  • 3%

  • 1%

  • 10%


B.

3%

10 volume H2O2 means 1mL of its solution on decomposition at NTP, give 10 mL oxygen gas. Volume of oxygen formed from 100 mL of solution at NTP = 1000 mL

2H2O22 moles2 × 34 gm  2H2O + O21 mole22400 mL

 22400 mL O2 formed at NTP by decomposition of 68 gm H2O2.

 1 mL O2 formed at NTP from 6822400 of H2O2

 1000 mL O2 formed at NTP from 68 × 100022400  g H2O2 = 3.035 g H2O2

So, concentration of 10 volume of H2Ois 3.0% (aprrox.)


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223.

One mole of magnesium nitride on the reaction with an excess of water gives

  • one mole of NH3

  • two moles of NH3

  • one mole of HNO3

  • two moles of HNO3


224.

2.5 L of NaCl solution contain 5 moles of the solute. What is the molarity ?

  • 5 M

  • 2 M

  • 2.5 M

  • 12.5 M


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225.

In acidic medium, the equivalent weight of  K2Cr2O7 ( Mol. wt. = M) is

  • M

  • M/2

  • M/3

  • M/6


226.

What is the total number of moles of H2SO4 needed to prepare 5.0 L at a 2.0M solution of H2SO4 ?

  • 2.5

  • 5.0

  • 10

  • 20


227.

In stoichiometric defect, the ratio of positive and negative ions as indicated by chemical formula of the compound

  • decreases

  • increases

  • changes by a factor of 2

  • remains same


228.

Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is

  • 2.28 mol kg-1

  • 3.28 mol kg-1

  • 0.44 mol kg-1

  • 1.14 mol kg-1


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229.

Consider the following reaction,

(CH3)3CCl + OH- → (CH3)3C-OH + Cl-

If OHdoes not take part in slow step, the molecularity and order of the reaction are respectively,

  • 2, 2

  • 2, 1

  • 1, 2

  • 1, 1


230.

When one litre one molar sulphuric acid solution is diluted with 5 L water, the normality of the obtained solution is

  • 0.2 N

  • 0.33 N

  • 10 N

  • 5 N


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