The crystal with metal deficiency defect is : from Chemistry The

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 Multiple Choice QuestionsMultiple Choice Questions

181.

Which of the following statement regarding defect is correct.

  • Due to Schottky defect, the density of crystalline solid decreases.

  • Due to Frenkel defect, the density of crystalline solid decreases.

  • Due to Schottky defect, entropy of solid decreases.

  • Due to Frenkel defect, entropy of solid decreases.


182.

Certain crystals produce electric signals on application of perssure. This phenomenon is called :

  • pyroelectricity

  • ferroelectricity

  • piezoelectricity

  • ferrielectricity


183.

Frenkel and Schottky defects are

  • nucleus defects

  • non-crystal defects

  • crystal defects

  • nuclear defects


184.

In the crystal of CsCl, the co-ordination number changes from 8:8 to 6:6 by:

  • applying high pressure

  • applying low temperature

  • applying high temperature

  • applying low pressure


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185.

A compound CuCl has face-centred cubic structure. Its density is 3.4 g cm-3 , The length of unit cell is:

  • 8.734 A0

  • 5.834 A0

  • 5.783 A0

  • 8.153 A0


186.

If the positions of Na+ and Cl- are interchanged in NaCl , the crystal lattice with respect to Na+ and CI- is:

  • bcc and fcc

  • fcc and bcc

  • both fcc

  • both bcc


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187.

The crystal with metal deficiency defect is :

  • NaCl

  • FeO

  • KCl

  • ZnO


B.

FeO

The metal deficiency defect arises due to the missing of a cation from its lattice site and presence of the cation with higher charge in the adjacent site. Hence, the metals showing variable valency like transition metal show this defect , e.g. , FeO.


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188.

ZnO is white when cold and yellow when heated. It is due to the development of

  • Frenkel defect

  • metal excess defect

  • Schottky defect

  • metal deficiency defect.


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189.

Among the following, the compound that is both paramagnetic and coloured is

  • K2Cr2O7

  • (NH4)2[TiCl6]

  • VOSO4

  • K3[Cu(CN)4]


190.

If an atom crystallises in bee lattice with r= 4 Å then the edge length will be

  • 2 Å

  • 8 Å

  • 2.39 Å

  • 9.23 Å


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