Excitation energy of a hydrogen like ion in its first excitation

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 Multiple Choice QuestionsMultiple Choice Questions

31.

Consider the spectral line resulting from the transition from n= 2 to n = 1, in atoms and ions given below. The shortest wavelength is produced by

  • hydrogen atom

  • deuterium atom

  • doubly ionized lithium

  • doubly ionized helium


32.

The energy of an electron in excited hydrogen atom is −3.4eV. Then according to Bohr's theory, the angular momentum of the electron is

  • 2.1 × 10-34 J-s

  • 3 × 10-34 J-s

  • 2 × 10-34 J-s

  • 0.5 × 10-34 J-s


33.

The solar spectrum during a complete solar eclipse is

  • continuous 

  • emission line

  • dark line

  • dark band


34.

A particle of mass M at rest decays into two masses m1 and m2 with non zero velocities. The ratio of de-Broglie wavelengths of the particles λ1λ2 is

  • m2m1

  • m1m2

  • m1m2

  • 1 : 1


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35.

For an electron in the second orbit of Bohr's hydrogen atom, the moment of linear momentum is

  • πh

  • 2πh

  • hπ

  • 2hπ


36.

If elements with principal quantum number n > 4 were not allowed in nature, the number of possible elements would have been

  • 32

  • 60

  • 64

  • 4


37.

The spectrum obtained from the chromosphere of the sun at the time of total solar eclipse is

  • line emission spectrum

  • band emission spectrum

  • continuous emission spectrum

  • line absorption spectrum


38.

Which state of triply ionised Beryllium (Be+++) has the same orbital radius as that of the ground state of hydrogen ?

  • n = 3

  • n = 4

  • n = 1

  • n = 2


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39.

If M is the atomic mass and A is the mass number, packing fraction is given by

  • MM - A

  • M - AA

  • AM - A

  • A -MA


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40.

Excitation energy of a hydrogen like ion in its first excitation state is 40.8 eV. Energy needed to remove the electron from the ion in ground state is

  • 40.8 eV

  • 27.2 eV

  • 54.4 eV

  • 13.6 eV


C.

54.4 eV

The excitation energy in the first excited state is

      E = RhcZ2 112 - 122         = 13.6 eV × Z2 × 34 Z = 2

So, the ion in problem is He+. The energy of the ion in the ground state is

E =- RhcZ212   = - 13.6 × 4 = -54.4 eV

Hence, 54.4 eV is required to remove the electron from the ion.


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