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 Multiple Choice QuestionsMultiple Choice Questions

81.

The force between two parallel current carrying wires is independent of

  • their distance of separation

  • the length of the wires

  • the magnitude of currents

  • the radii of the wires


82.

The graph between resistivity and temperature, for a limited range of temperatures, is a straight line for a material like

  • copper

  • nichrome

  • silicon

  • mercury


83.

In the circuit shown, the current through the 5 Ω resistor is

  • 83 A

  • 913 A

  • 413 A

  • 13 A


84.

A 100 W bulb produces an electric field of 2.9 Vm-1 at a point 3 m away. If the bulb is replaced by 400 W bulb without distributing other conditions, then the electric field produced at the same point is

  • 2.9 Vm-1

  • 3.5 Vm-1

  • 5 Vm-1

  • 5.8 Vm-1


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85.

In the given circuit the current through the battery is

  • 0.5 A

  • 1 A

  • 1.5 A

  • 2 A


86.

In the circuit shown, the current through 8 Ω is same before and after connecting E. The value of E is

  • 12 V

  • 6 V

  • 4 V

  • 2 V


87.

An electric bulb rated 500 W at 100 V is used in a circuit having a 200 V supply. The resistance R that must be put in series with the bulb, so that the bulb draws 500 W is

  • 10 Ω

  • 15 Ω

  • 20 Ω

  • 25 Ω


88.

Two copper wires have their masses in the ratio 2 : 3 and the lengths in the ratio 3 : 4.The ratio of their resistances is

  • 4 : 9

  • 27 : 32

  • 16 : 9

  • 27 : 128


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89.

Two different conductors have same resistance at 0°C. It is found that the resistance of the first conductor at t1°C is equal to the resistance of the second conductor at t2°C. The ratio of the temperature coefficients of resistance of the conductors, α1α2 is

  • t1t2

  • t2 - t1t2

  • t2 - t1t1

  • t2t1


D.

t2t1

Resistance of a conductor varies linearly with temperature as

Rt = R0 1 + αt

for first conductor

     Rt = R0 1 + α1t1or  α1 = Rt1 - R0t1                                ........ (i)

Similarly, for second conductor

α2 = Rt2 - R0t2                              ......... (ii)

From Eqs. (i) and (ii) we get

α1α2 = t2t1


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90.

In the given circuit diagram the current through the battery and the charge on the capacitor respectively in steady state are

  • 1 A and 3 µC

  • 17 A and 0 µC

  • 11 A and 3 µC

  • 6 A and 0 µC


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