The displacement of a particle along the x-axis is given by x =

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

111.

If we study the vibration of a pipe open at both ends, then the following statements is not true

  • open end will be anti-node

  • Odd harmonics of the fundamental frequency will be generated

  • All harmonics of the fundamental frequency will be generated

  • All harmonics of the fundamental frequency will be generated

1976 Views

112.

A source of unknown frequency gives 4 beats/s when sounded with a source of known frequency 250 Hz. The second harmonic of the source of unknown frequency gives five beats per second when sounded with a source of frequency 5.13 Hz. The unknown frequency is

  • 250 Hz

  • 246 Hz

  • 240 Hz

  • 240 Hz

2204 Views

113.

Out of the following functions representing motion of a particle which represents SHM

space straight I space. space straight y space equals space sin space ωt space minus space cos space ωt

II. space straight y space equals space sin squared space ωt

III. space straight y space equals space 5 space cos space open parentheses fraction numerator 3 straight pi over denominator 4 end fraction minus space 3 space ωt close parentheses

IV. space straight y space equals space 1 space plus space ωt space plus space straight omega squared straight t squared

  • Only (IV) does not represent SHM

  • (I) and (III)

  • (I) and (II)

  • (I) and (II)

764 Views

114.

A string is stretched between fixed points separated by 75.0 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencies between these two. The lowest resonant frequency for this strings is

  • 155 Hz

  • 205 Hz

  • 10.5 Hz

  • 10.5 Hz

2024 Views

Advertisement
115.

A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then, its time period of vibration will be 

  • β22

  • α/β

  • β2

  • β2

2855 Views

116. If space vectors space straight A space equals space space cos space ωt space straight i with hat on top space plus space sin space straight omega straight j with hat on top space and space straight B space equals space cos space ωt over 2 straight i with hat on top space plus space sin ωt over 2 straight j with hat on top are functions of time, then the value of t at which they are orthogonal to each other
  • straight t space equals space fraction numerator straight pi over denominator 4 straight omega end fraction
  • straight t space equals space fraction numerator straight pi over denominator 2 straight omega end fraction
  • t equals space straight pi over straight omega
  • t equals space straight pi over straight omega
497 Views

117.

Two particle are oscillating along two close parallel straight lines sides by sides, with the same frequency and amplitudes. They pass each other, moving in opposite directions when their displacement is half of the amplitude. The mean position of the two particles lie on a straight line perpendicular to the paths of the two particles.
The phase difference is

  • zero

  • 2π/3

  • π

  • π

1028 Views

Advertisement

118.

The displacement of a particle along the x-axis is given by x = a sin2 ωt. The motion of the particle corresponds to 

  • simple of harmonic motion of frequency ω/π

  • simple harmonic motion of frequency 3ω/2π

  • non simple harmonic motion

  • non simple harmonic motion


D.

non simple harmonic motion



The given equation does not satisfy the condition for SHM (Eq. (i) ]. Therefore, motion is not simple harmonic.
1302 Views

Advertisement
Advertisement
119.

The period of oscillation of mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be

  • T

  • straight T divided by square root of 2
  • 2T

  • 2T

1039 Views

120.

A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. the speed of the pendulum at x = a/2 will be

  • fraction numerator πa space square root of 3 over denominator 2 straight T end fraction
  • πa / T

  • 2a / T

  • 2a / T

779 Views

Advertisement