If the length of a pendulum is made 9 times and mass of the bob is made 4 times, then the value of time period becomes :
3 T
3/2T
4T
2T
A pendulum is undergoing SHM with frequency f What is the frequency of its kinetic energy ?
2 f
3 f
4 f
Two equal -ve charges -q are fixed at the point (O, a) and (O, a) on the y-axis. A positive charge Q is released from rest at the point (2a, 0) on the x-axis. The charge will :
execute SHM about the origin
move to the origin and remain at rest
move to infinity
execute oscillatory but not SHM
The circular motion of a particle with constant speed is
simple harmonic but not periodic
periodic and simple harmonic
neither periodic nor simple harmonic
periodic but not simple harmonic
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
3 Hz
2 Hz
4 Hz
1 Hz
A particle executes simple harmonic oscillation with an amplitude . The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
Given that , where y and x are measured in metre. Which of the following statements is true?
The unit of λ is same as that of x and A
The unit of λ is same as that of x but not of A
The unit of c is same as that of
The unit of ( ct - x ) is same as that of
Two simple pendulums of length 0.5 m and 20 m respectively are given small linear displacement in one direction at the same time. They will again be in the phase when the pendulum of shorter length has
completed x oscillations, where k is
1
3
2
5
A mass of 1 kg is suspended from a spring of force constant 400 N, executing SHM total energy of the body is 2J, then maximum acceleration of the spring will be
4 m/s2
40 m/s2
200 m/s2
400 m/s2
B.
40 m/s2
Oscillations due to spring
T = 2
Where T is the time period
k is spring constant
m is mass attached to spring
T =
= 2
=
Frequency n =
ω = 2π n
= 2π ×
ω = 20
Total energy
E =
2 =
r =
Acceleration = ω2 r
= 400
= 40 m/s2
Vibrations of rope tied by two rigid ends shown by equation y = cos 2πt sin2πx, then minimum length of the rope will be
1 m
5 m
2πm