In Δ ABC,  and , if BD = 3 cm and CD = 4 cm, then the lengt

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51.

In Δ ABC, angle BAC space equals space 90 degree and AD space perpendicular space BC, if BD = 3 cm and CD = 4 cm, then the length of AD is

  • 3.5 cm

  • 5 cm

  • 2 square root of 3 space cm
  • 2 square root of 3 space cm


C.

2 square root of 3 space cm

BD = 3 cm
CD = 4cm
In Δ ABC
AB2 + AC2 = 72 = 49   ...(i)
In Δ ABD,
AB2 = AD2 + 32 = AD2 + 9  ...(ii)
In Δ ADC,
AC2 = AD2 + 16        ...(iii)
Add equations (ii) and (iii)
AB2 + AC2 = AD2 + 9 + AD2 + 16
⟹  49 = 2AD2 + 25
⟹  2AD2 = 49 - 25 = 24
⟹  AD2 = 12
⟹  AD space equals space square root of 12 space equals space 2 square root of 3 space cm.




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52.

The centroid of a Δ ABC is G. The area of Δ ABC is 60 cm2. The area of ΔGBC is

  • 10 cm2

  • 30 cm2

  • 40 cm2

  • 40 cm2

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53.

AD is perpendicular to the internal bisector of angle BAC of Δ ABC. DE is drawn through D and Parallel to BC to meet AC at E. If the length of AC is 12 cm, then the length of AE (in cm.) is

  • 3

  • 8

  • 4

  • 4

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54.

Δ ABC is similar to ΔDEF. If the area of ΔABC is 9 sq. cm. and the area of ΔDEF is 16 sq. cm. and BC = 2.1 cm, then the length of EF will be

  • 5.6 cm

  • 2.8 cm.

  • 3.7 cm.

  • 3.7 cm.

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55.

Let G be the centroid of the equilateral triangle ABC of perimeter 24 cm. Then the length of AG is

  • 2√3 cm

  • 8⁄√3 cm

  • 8√3 cm

  • 3√8 cm

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56.

If D and E are the mid-points of AB and AC respectively of ΔABC, then the ratio of the areas of Δ ADE and ◻BCED is

  • 1 : 2

  • 1 : 4

  • 3 : 1

  • 1 : 3

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57.

O is the circumcentre of the isosceles △ABC. Given that AB = AC = 5 cm and BC = 6 cm. The radius of the circle is

  • 3.015 cm

  • 3.205 cm

  • 3.025 cm

  • 3.125 cm

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58.

B1 is a point on the side AC of ΔABC and B1B is joined. A line is drawn through A parallel to B1B meeting BC at A1 and another line is drawn through C parallel to B1B meeting AB produced at C1. Then

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59.

I is the incentre of Δ ABC and if ∠BAC = 70°, then ∠BIC is

  • 140°

  • 55°

  • 125°

  • 35°

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60.

In a Δ ABC, D and E are points on AC and BC respectively, AB and DE are perpendicular to BC. If AB = 9cm, DE = 3 cm and AC  = 24 cm, then AD is

  • 32 cm

  • 16 cm

  • 8 cm

  • 4 cm

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