PQR is an equilateral triangle. MN is drawn parallel to QR such

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 Multiple Choice QuestionsMultiple Choice Questions

61.

The perimeter of two similar triangles ΔABC and ΔPQR are 60 cm and 36 cm respectively. If PQ = 18 cm, then AB is

  • 20 cm

  • 24 cm

  • 36 cm

  • 36 cm

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62.

In a ΔABC, if angle straight A space plus space angle straight B space equals space 135 degreeand  angle straight C space plus space 2 angle straight B space equals space 180 degree then the correct relation is

  • CA > AB

  • CA = AB

  • CA < AB

  • CA + AB = CB

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63.

Which of the following ratios can be the ratio of the sides of a right-angled triangle?

  • 9 : 6 : 3

  • 13 : 12 : 5

  • 7 : 6 : 5

  • 7 : 6 : 5

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64.

PQR is an equilateral triangle. MN is drawn parallel to QR such that M is on PQ and N is on PR. If PN = 6 cm, then the length of MN is

  • 3 cm

  • 6 cm

  • 12 cm

  • 12 cm


B.

6 cm

Δ PMN will also be an equilateral triangle.
As PN = 6 cm
∴  MN = 6 cm   [Sides of an equilateral triangle are always equal].
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65.

In  Δ ABC,  DE || AC, where D and E are two points lying on AB and BC respectively. If AB = 5 cm and AD = 3 cm, then BE : EC is

  • 2 : 3

  • 3 : 2

  • 5 : 3

  • 3 : 5

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66.

D, E, F are the mid-points of the sides BC, CA and AB respectively of a Δ ABC. Then the ratio of the areas of Δ DEF and Δ ABC is:

  • 1/2

  • 1/4

  • 1/8

  • 1/16

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67.

The orthocentre of a triangle is the point where

  • the medians meet

  • the altitudes meet

  • the right bisectors of the sides of triangle meet

  • the right bisectors of the sides of triangle meet

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68.

G is the centroid of Δ ABC. If AG = BC, then measure of ∠BGC  is

  • 45°

  • 60°

  • 90°

  • 120°

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69.

The ratio of the angles of a triangle is 1 space colon space 2 over 3 space colon space 3. Then the smallest angle is:

  • 21 fraction numerator 4 degree over denominator 7 end fraction

  • 25 degree

  • 25 fraction numerator 5 degree over denominator 7 end fraction

  • 25 fraction numerator 5 degree over denominator 7 end fraction

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70.

In an isosceles triangle ABC, AB = AC and angle straight A space equals space 80 degree comma the bisector of angle straight B and angle straight C meet at D. The angle BDC is equal to

  • 90°

  • 100°

  • 130°

  • 80°

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