The sum of 10 terms of the arithmetic series is 390. If the third term of the series is 19, find the first term:
3
5
7
7
A.
3
According to the question,
a + a+d + a+ 2d + a+3d + a+4d + a+5d + a+6d + a+7d + a+8d + a+9d = 390
10a + 45d = 390.....(i)
a + 2d = 19
or
10a + 20d = 190 ....(ii)
Solve (i) and (ii),
25d = 200
d = 8
Put the value of d = 8 in equation (i)
a = 19 - 2 x8 = 19 - 16 = 3, a = 3.(the first term)
What least value must be assigned to '*' so that the number 63576*2 is divisible by 8?
1
2
3
4
Which one of the following is the minimum value of the sum of two integers whose product is 24?
25
11
8
10
A number, when divided by 114, leaves remainder 21. If the same number is divided by 19, then the remainder will be
1
2
7
17
A number when divided by 49 leaves 32 as remainder. This number when divided by 7 will have the remainder as
4
3
2
5