The sum of 10 terms of the arithmetic series is 390. If the third term of the series is 19, find the first term:
3
5
7
7
What least value must be assigned to '*' so that the number 63576*2 is divisible by 8?
1
2
3
4
Which one of the following is the minimum value of the sum of two integers whose product is 24?
25
11
8
10
A number, when divided by 114, leaves remainder 21. If the same number is divided by 19, then the remainder will be
1
2
7
17
A number when divided by 49 leaves 32 as remainder. This number when divided by 7 will have the remainder as
4
3
2
5
The remainder when 321 is divided by 5 is
1
2
3
4
C.
3
The unit digit of 321 is 3.
The remainder, when a number is divided by 5, always the unit digit itself. i .e. 3 is the right answer.