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Data Handling

Multiple Choice Questions

31.

·Data handling' at upper primary stage focuses on

data organisation only
techniques of data collection
data collection, organisation and interpretation
data interpretation only

32.

The sum of mean, mode and median of the data 6, 3, 9, 5, 1, 2, 3, 6, 5, 1, 3 is

33.

Natural numbers 4 to 15 are written on different slips (one number on one slip), kept in a box and mixed well. Renu picks up one slip from the box without looking into it. What is the probability that this slip bears a prime number?

$\frac{1}{3}$
$\frac{5}{12}$
$\frac{2}{5}$
$\frac{3}{11}$

34.

There are 10 persons in a party. If each one of them shakes hand with others exactly once. The total number of handshakes is

105
55
45
None of these

35.

A man and his wife appear for an interview for two posts. The probability of husband's selection is $\frac{1}{7}$ and that of wife's selection $\frac{1}{5}$ . What is the probability of only one of them will be selected ?

$\frac{1}{7}$
$\frac{2}{7}$
$\frac{2}{5}$
$\frac{1}{5}$

36.

Out of 12 observations arranged in ascending order, the sixth and seventh observations are 14 and 15 respectively. Find the median of all the 12 observations.

29
14.5
15
None of these

37.

The mean of mode, median and range of the data 2, 1, 2, 3, 3, 6, 4, 8, 14, 9, 4, 8, 4 is

38.

Which one of the following activities is not appropriate for 'data representation and data interpretation'?

Survey
Debate
Newspaper report
Project

39.
$If x = \frac{2}{3} and y = \frac{3}{4}, then a rational number between {(x - y)}^{- 1} and (x^{- 1} - y^{- 1}) is$

$\frac{2}{3}$

$- \frac{71}{2}$

$- \frac{71}{12}$

$\frac{1}{6}$

$- \frac{71}{12}$

$Given, x = \frac{2}{3} and y = \frac{3}{4} ∴ x^{- 1} = \frac{1}{x} = \frac{3}{2} and y^{- 1} = \frac{1}{y} = \frac{4}{3} Now, {(x - y)}^{- 1} = {(\frac{2}{3} - \frac{3}{4})}^{- 1} = {(\frac{2 \times 4}{3 \times 4} - \frac{3 \times 3}{4 \times 3})}^{- 1} = {(\frac{8}{12} - \frac{9}{12})}^{- 1} = {(\frac{- 1}{12})}^{- 1} = - 12 = \frac{- 12 \times 12}{12} = \frac{- 144}{12} and x^{- 1} - y^{- 1} = \frac{3}{2} - \frac{4}{3} = \frac{3 \times 3}{2 \times 3} - \frac{4 \times 2}{3 \times 2} = \frac{9}{6} - \frac{8}{6} = \frac{1}{6} = \frac{1 \times 2}{6 \times 2} = \frac{2}{12} Here, \frac{- 71}{12} lie between - \frac{144}{12} and \frac{2}{12}$