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 Multiple Choice QuestionsMultiple Choice Questions

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291.

Among the following, the pair in which the two species are not isostructural, is

  • SiF4 and SF4

  • IO3- and XeO3

  • BH4- and NH4+

  • PF6- and SF6


A.

SiF4 and SF4

SiF4 and SF4 are not isostructural because SiF4 is tetrahedral due to sp3-hybridisation of Si.

14Si = 1s2, 2s2, 2p6, 3s2 3p2 (In ground state)

14Si = 1s2, 2s2, 2p6, 3s1 3p3 (In excited state)

Hence, four equivalent sp3-hybrid orbitals are obtained and they are overlapped by four
p-orbitals of four fluorine atoms on their axes. Thus, it shows following structure:

While SF4 is not tetrahedral but it is distorted tetrahedral because in it S is sp3d hybrid and has a lone pair of electron.

16S = 1s2, 2s2 2p6, 3s23px23py13pz1 (In ground state)

     = 1s2, 2s2 2p63s23px13py13pz1, 3dxy1sp3d hybridisation (In first excitation state)

Hence, sp3d hybrid orbitals are obtained. One orbital is already paired and rest four are overlapped with four p-orbitals of four fluorine atoms on their axes in trigonal bipyramidal form. This structure is distorted from trigonal bi-pyramidal to tetrahedral due to involvement of repulsion between lone pair and bond pair. 


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292.

The helical structure of protein is stabilized by

  • dipeptide bond

  • hydrogen bonds

  • ether bonds

  • peptide bonds


293.

The dipole moment of HBr is 1.6 × 10-30 cm and inter-atomic spacing is 1 Å. The % ionic character of HBr is

  • 7

  • 10

  • 15

  • 27


294.

The bond angle is smallest in

  • H2O

  • H2S

  • BeCl2

  • N2O


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295.

Valence bond theory of metallic bond was given by

  • Dalton

  • Drudel

  • Fajan

  • Pauling 


296.

Which combination of atoms can form a polar covalent bond ?

  • H and N

  • H and Br

  • N and N

  • Na and Br


297.

The bond length of H2+, H2- and H2 are in the following order

  • H2+ > H2 > H2-

  • H2H2+ > H2-

  • H2- > H2 > H2+

  • H2- > H2+ > H2


298.

The correct order of bond length is

  • b > a > c > d

  • a > b > c > d

  • d > c > b > a

  • c > d > b > a


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299.

Consider the following ions:

(i) Ni2+   (ii) Co2+  (iii) Cr2+   (iv) Fe3+

(Given, at. no. Cr = 24, Fe = 26, Co = 27, Ni = 28)

The correct order of magnetic moment of these ions is

  • (i) < (ii) < (iii) < (iv)

  • (iv) < (ii) < (iii) < (i)

  • (i) < (iii) < (ii) < (iv)

  • (iii) < (iv) < (ii) < (i)


300.

Geometry of methyl free radical is

  • pyramidal

  • planar

  • tetrahedral

  • linear


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