Assertion (A): K, Rb and Cs form superoxides.Reason (R): The stability of the superoxides increases from K to Cs due to decrease in lattice energy.The correct answer is | Classification of Elements and Periodicity in Properties

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 Multiple Choice QuestionsMultiple Choice Questions

31.

What is the value of electron gain enthalpy of Na if IE1 of Na = 5.1 eV?

  • -5.1 eV

  • -10.2 eV

  • +2.55 eV

  • +10.2eV


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32.

Assertion (A): K, Rb and Cs form superoxides.

Reason (R): The stability of the superoxides increases from 'K' to 'Cs' due to decrease in lattice energy.

The correct answer is

  • Both (A) and (R) are true and (R) is the correct explanation of (A).

  • Both (A) and (R) are true but (R) is not the correct explanation of (A)

  • (A) is true but (R) is not true

  • (A) is not true but (R) is true


C.

(A) is true but (R) is not true

Superoxides are the species having an O-O bond and O in an oxidation state of -12  (superoxide ion is O2-). Usually these are formed by active metals such as KO2, RbO2 and CsO2. For the salts of larger anions (like O2-), lattice energy increases in a group. Since, lattice energy is the driving force for the formation of an ionic compound and its stability, the stability of the superoxides from 'K' to 'Cs' also increases.


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33.

Which one of the following order is correct for the first ionisation energies of the elements?

  • B <Be <N < O

  • Be <B <N < O

  • B <Be <O <N

  • B <O <Be <N


34.

The oxidation number of oxygen in KO3, Na2O2 is

  • 3, 2

  • 1, 0

  • 0, 1

  • -0.33, -1


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35.

What is the fuel of atomic pile ?

  • Thorium

  • Sodium

  • Uranium

  • Petroleum


36.

The maximum number of unpaired electrons is present in

  • Fe

  • Cu

  • Co

  • Ni


37.

The pair, that is referred as 'chemical twins' is

  • Ac, Cf

  • Hf, Ta

  • Tc, Re

  • La, Ac


38.

Ce4+ is stable. This is because of

  • half-filled d-orbitals

  • all paired electrons ind-orbitals

  • empty orbital

  • fully filled d-orbital


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39.

What is the orbital angular momentum of an electron in 'f'  orbital?

  • 1.5hπ

  • 6hπ

  • 3hπ

  • 3h2π


40.

Fool's gold is

  • Cu2S

  • FeS2

  • Al2O5

  • CuFeS2


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