Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

81.

A point moves, so that the sum of squares of its distance from the points (1, 2) and (- 2, 1) is always 6. Then, its locus is

  • the straight line y - 32 = - 3x + 12

  • a circle with centre - 12, 32 and radius 12

  • a parabola with focus (1, 2) and directrix passing through (- 2, 1)

  • an ellipse with foci (1, 2) and (- 2, 1)


82.

A circle passing through (0, 0), (2, 6), (6, 2) cut the x-axis at the point P  (0, 0). Then, the lenght of OP, where O is the origin, is

  • 52

  • 52

  • 5

  • 10


Advertisement

83.

If one end of a diameter of the circle 3x2 + 3y2 - 9x + 6y + y = 0  is (1, 2), then the other end is

  • (2, 1)

  • (2, 4)

  • (2, - 4)

  • (- 4, 2)


C.

(2, - 4)

Given equaitson of circle is,

3x2 + 3y- 9x + 6y + 5 = 0

 x2 + y2 - 3x + 2y + 53 = 0      Centre = 32, - 1and radius = 94 + 1 - 53                 = 1912                 = 12193

We know that, centre of the circle is the mid-point of the diameter.

Lives one and of point of dianetev in (1, 2) Let the other end point of diameter is (h, k)

Then, 32, - 1 = 1 + h2, 2 +k2         1 +h2 = 32           1 +h = 3                  h = 2and 2 + k2 = - 1    2 + k = - 2            k = - 4

So, the other end point is (2, - 4).


Advertisement
84.

The line y = x intersects the hyperbola x29 - y225 = 1 at the points P and Q. The eccentricity of ellipse with PQ as major axis and minor axis of length 52 is

  • 53

  • 53

  • 59

  • 229


Advertisement
85.

If the distance between the foci of an ellipse is equal to the length of the latusrectum, then its eccentricity is

  • 145 - 1

  • 125 + 1

  • 125 - 1

  • 145 + 1


86.

The equation of the circle passing through the point (1, 1) and the points of intersection of x2 + y2 -  6x - 8 = 0 and x2 + y2 - 6 = 0 is 

  • x2 + y2 + 3x - 5 = 0

  • x2 + y2 - 4x + 2 = 0

  • x2 + y2 + 6x - 4 = 0

  • x2 + y2 - 4y - 2 = 0


87.

The area of the region bounded by the parabola y = x2 - 4x + 5 and the straight line y= x + l is

  • 12

  • 2

  • 3

  • 92


88.

The equation y2 + 4x + 4y + k = 0 represents a parabola whose latusrectum is

  • 1

  • 2

  • 3

  • 4


Advertisement
89.

If the circles x2 + y2 + 2x + 2ky + 6 = 0 and x2 + y+ 2ky + k = 0 intersect orthogonally, then k is equal to

 

  • 2 or - 32

  • - 2 or - 32

  • 2 or  32

  • - 2 or  32


90.

If four distinct points (2k, 3k), (2, 0), (0, 3), (0, 0) lie on a circle, then

  • k < 0

  • 0 < k < 1

  • k = 1

  • k > 1


Advertisement