If the vertex is (3,0) and the extremities of the latusrectum are (4, 3) and (4, - 3), then the equation of the parabola is
y2 = 4(x - 3)
x2 = 4(y - 3)
y2 = - 4(x + 3)
x2 = - 4(y + 3)
If the line x + 2by + 7 = 0 is a diameter of the circle x2 + y2 - 6x + zy = 0, then b is equal to
- 5
- 3
2
5
The number of circles that touch all the straight lines x + y = 4,x - y = - 2 and y = 2 is
1
2
3
4
D.
4
There are four circles can be drawn which touch all the lines.
The equation of the normal to the circle x2 + y2 + 6x + 4y - 3 = 0 at (1, - 2) is
y + 1 = 0
y + 2 = 0
y + 3 = 0
y - 2 = 0
The limiting points of the co-axial system containing the two circles x2 + y2 + 2x - 2y + 2 = 0 and 25(x2 + y) - 10x - 80y + 65 = 0 are
(1, - 1), (- 3, - 40)
The radical axis of circles x2 + y2 + 5x + 4y - 5 = 0 and x2 + y2 - 3x + 5y - 6 = 0 is
8y - x + 1 = 0
8x - y+ 1 = 0
8x - 8y + 1 = 0
y - 8x + 1 = 0
If the normal to the parabola y2 = 4x at P(1, 2) meets the parabola again in Q, then coordinates of Q are
(- 6, 9)
(9, - 6)
(- 9, - 6)
(- 6, - 9)